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3 years ago

Moles of phosphorous in 15-35-15 fertilizer in 10g

1 answer:

6 0

The composition of a fertilizer is usually express in NPK number. NPK number is in terms of Percent by mass of the said element which are Nitrogen, Phosphorus and Potassium. A 15-35-15 fertilizer has 15% Nitrogen, 35% Phosphorous, and 15% Potassium by mass. If you have 10 g of this fertilizer, to get the number of moles of phosphorus, you multiply the mass by 35%, which is equal to 10*0.35 or 3.5 g phosphorus. Then you divide the calculated mass of phosphorous by its molar mass which is 30.97 g/mol. Therefore, you have 3.5/30.97 which is equal to 0.1130 mol Phosphorus. This is the amount of Phosphorus in moles in the fertilizer.

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svet-max [94.6K]

No of protons=No of electrons=15

<h3>Mass no:-No of neutrons+No of protons </h3>

$\\ \tt\longmapsto 15+16=31$

Now

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$\\ \tt\longmapsto 1s^22s^22p^63s^23p^3$ .

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$\\ \tt\longmapsto XCl_3$

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