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solong [7]
4 years ago
15

Moles of phosphorous in 15-35-15 fertilizer in 10g

Chemistry
1 answer:
guapka [62]4 years ago
6 0

<span>The composition of a fertilizer is usually express in NPK number. NPK number is in terms of Percent by mass of the said element which are Nitrogen, Phosphorus and Potassium. A 15-35-15 fertilizer has 15% Nitrogen, 35% Phosphorous, and 15% Potassium by mass. If you have 10 g of this fertilizer, to get the number of moles of phosphorus, you multiply the mass by 35%, which is equal to 10*0.35 or 3.5 g phosphorus. Then you divide the calculated mass of phosphorous by its molar mass which is 30.97 g/mol. Therefore, you have 3.5/30.97 which is equal to 0.1130 mol Phosphorus. This is the amount of Phosphorus in moles in the fertilizer.</span>

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lisabon 2012 [21]

The answer would be scoria I believe

8 0
3 years ago
How does the proximity to water affect temperature and precipitation in the tropical, temperate, and polar zones?
Zolol [24]

Answer:

Water heats and cools more slowly than landmasses.

Explanation:

because the coastal regions will stay cooler in summer and warmer in winter but creating a more moderate climate with a narrower temperature range.

5 0
3 years ago
In the combined gas law, if the pressure in the system is increased, what happens to the volume if temperature remains constant?
ANEK [815]
Boyle's law<span> states that, at a </span>constant temperature<span>, the </span>volume of<span> a given mass </span>of gas<span> varies inversely with </span>pressure<span>. ... Thus Charles's </span>law<span> states that at a </span>constant pressure<span>, the </span>volume of<span> a given mass </span>of gas<span> is directly proportional to its (absolute)</span>temperature<span>.</span>
7 0
3 years ago
Read 2 more answers
The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argo
noname [10]

Answer:

<h2>36.09 L</h2>

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

V_1 =  \frac{P_2V_2}{P_1}  \\

We have

V_1 =  \frac{7.98 \times 14.2}{3.14} =   \frac{113.316}{3.14}  \\  = 36.0878...

We have the final answer as

<h3>36.09 L</h3>

Hope this helps you

8 0
3 years ago
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A second step is to look at its structure. Double bonds are traditionally shorter than single bonds; triple bonds shorter still. Covalent bonds do have typical lengths, nevertheless you can still have problems.

<span>A third step is to consider reactivity. For example, if you have a C=C double bond, you can add, say, bromine to it Thus C2H4 gives C2H4Br2, and by adding two bromine atoms you know you have one double bond. Again, benzene becomes an awkward molecule, but because of this, you know benzene does not have double bonds in the traditional sense</span>
8 0
3 years ago
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