Answer:
136.36 mL
Explanation:
Here we have to use the dilution formula
From C1V1= C2V2
Where;
C1= initial concentration of the solution= 12.0 M
C2= final concentration of the solution= 2.20 M
V1 = initial volume of the solution= 25.0 ml
V2= final volume of the solution= ?????
Then recall;
C1V1=C2V2
V2 = C1V1/C2
Substituting values from the parameters given;
V2= 12.0 × 25.0 / 2.20
V2= 136.36 mL
The third class lever s<span>have </span>the effort<span> placed amongst </span>load<span> and the fulcrum.</span>
it would be heating of 32g of s and 56g of Fe to produce 88g of FeS and unused reactants
Moles of ammonia
- Given mass/Molar mass
- 230/17
- 13.5mol
1mol requires 5.66KJ energy
13.5mol requires