A level chem naming isomers
1 answer:
Answer:
Butan-1-ol or Butanol
2-methylpropan-2-ol
2-methylpropan-1-ol
Explanation:
Data Give:
Three Isomers are given
names of These =?
Details:
Isomers:
Isomers are those chemical compounds that have same molecular formula but different structures.
In the given question the compound have same molecular formula that is C₄H₉OH but the structures are different.
So due to different structures they are named differently.
The 1st one is straight and the other two are branched
Names are given in attachment
butan-1-ol or Butanol
As it contain 4 carbon atoms an -OH group is attached at position 1.
________________
2-methylpropan-2-ol
In this -OH and -CH₃ is attached on carbon 2
_____________
2-methylpropan-1-ol
In this -CH₃ attached at position 2 and -OH is attached on Carbon 1.
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Answer:
The scaling factor is 5.
Explanation:
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In this case, since the scaling factor is defined as the ratio of the molar mass of the molecular formula (complete) to the empirical formula (simplified), it is possible to compute it for the empirical formula of CH2O whose molar mass is 30 g/mol (12+2+16) as shown below:
Therefore, we can also infer that the molecular formula would be:
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Answer:
Final pressure in (atm) (P1) = 6.642 atm
Explanation:
Given:
Initial volume of gas (V) = 12.5 L
Pressure (P) = 784 torr
Temperature (T) = 295 K
Final volume (V1) = 2.04 L
Final temperature (T1) = 310 K
Find:
Final pressure in (atm) (P1) = ?
Computation:
According to combine gas law method:
⇒ Final pressure (P1) = 5,048.18877 torr
⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760
⇒ Final pressure in (atm) (P1) = 6.642 atm