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3 years ago

A level chem naming isomers

Chemistry

1 answer:

victus00 [196]3 years ago

5 0

Answer:

Butan-1-ol or Butanol

2-methylpropan-2-ol

2-methylpropan-1-ol

Explanation:

Data Give:

Three Isomers are given

names of These =?

Details:

Isomers:

Isomers are those chemical compounds that have same molecular formula but different structures.

In the given question the compound have same molecular formula that is C₄H₉OH but the structures are different.

So due to different structures they are named differently.

The 1st one is straight and the other two are branched

Names are given in attachment

butan-1-ol or Butanol

As it contain 4 carbon atoms an -OH group is attached at position 1.

________________

2-methylpropan-2-ol

In this -OH and -CH₃ is attached on carbon 2

_____________

2-methylpropan-1-ol

In this -CH₃ attached at position 2 and -OH is attached on Carbon 1.

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Explanation:

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3 years ago

kifflom [539]

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Leona [35]

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Oxygen gas is collected over water. The total pressure (the O2 pressure the water vapor pressure) is 736 torr. The temperature o

tigry1 [53]

Answer:

The value of the partial pressure of the oxygen $P_{O_{2} }$ = 690 torr

Explanation:

Total pressure of the mixture of gases = 736 torr

The partial pressure of water vapor = 46 torr

From the law of pressure we know that

Total pressure = The partial pressure of water vapor + The partial pressure of oxygen $O_{2}$

Put the values of pressures in above equation we get,

⇒ 736 = 46 + $P_{O_{2} }$

⇒ $P_{O_{2} }$ = 736 - 46

⇒ $P_{O_{2} }$ = 690 torr

This is the value of the partial pressure of the oxygen.

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3 years ago

Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.

sammy [17]

A electrochemical reaction is said to be spontaneous, if $E^{0} cell is positive.$

Answer 1:
Consider reaction: Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
 $S^{2-}/S // Ni^{2+}/Ni$

Hence, $E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}$
we know that, ${E^{0} Ni^{2+}/Ni = -0.25 v$
and ${E^{0} S/ S^{2-} = -0.47 v$

Therefore, $E^{0} cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
 $H_{2} / H^{+} // Pb^{2+} /Pb$

Hence, $E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}$
we know that, ${E^{0} Pb^{2+}/Pb = -0.126 v$
and ${E^{0} H_{2}/ H^{+} = -0 v$

Therefore, $E^{0} cell$ = - 0.126 - 0 = -0.126 v

Since, $E^{0} cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
 $Cr/Cr^{2+} // Ag^{+}/Ag$

Hence, $E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}$
we know that, ${E^{0} Ag^{+}/Ag = -0.22 v$
and ${E^{0} Cr/ Cr^{2+} = -0.913 v$

Therefore, $E^{0} cell$ = - 0.22 - (-0.913) = 0.693 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous

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A level chem naming isomers​

A level chem naming isomers