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I am Lyosha [343]
3 years ago
10

A vector has an x-component of 19.5m and a y-component of 28.4m. Find the magnitude and direction of the vector

Physics
1 answer:
Zanzabum3 years ago
6 0

Answer:

34.5 m at 55.5 degrees above the positive x-axis

Explanation:

Resolving a vector means finding its components along two perpendicular axis: most commonly, they are chosen as the x and y axis.

In this problem, we have a vector whose components are:

x -component: 19.5 m

y- component: 28.4 m

The two components are perpendicular to each other: this means that we can find the magnitude of the vector by using the Pythagorean theorem

v=\sqrt{v_x^2+v_y^2}=\sqrt{19.5^2+28.4^2}=34.5 m

The direction, instead, can be found by using the following formula:

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1} (\frac{28.4}{19.5})=55.5^{\circ}

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using newtons law a force of 250N is applied to an object that accelerates at a rate of 5M/s2 what is the mass of the object?
AURORKA [14]

Answer:

50 kg

Explanation:

F = ma

250 N = m (5 m/s²)

m = 50 kg

7 0
3 years ago
A ball is thrown upwards at an unknown speed. in a time of
alexandr402 [8]

Answer:

a)  Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a)  We have equation of motion s=ut+\frac{1}{2} at^2, where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8m/s^2

 Substituting

    6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s

 Initial speed of the ball = 14.45 m/s

 b) We have equation of motion v^2=u^2+2as, where v is the final velocity

   s = 6 m, u = 14.45 m/s, a = -9.8m/s^2

    Substituting

        v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s

  So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion v^2=u^2+2as, where v is the final velocity

   u = 14.45 m/s, v =0 , a = -9.8m/s^2

   Substituting

     0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m

  Maximum height reached = 10.65 m

8 0
3 years ago
HELP
dem82 [27]

Answer:

Explanation:

28 / 70 = 0.3857142...  = 0.39 hr

280 / 100 = 2.8 hrs.

(100 - 0) / 10 = 10 m/s²

(60 - 20) / 4 = 10 m/s²

3 0
2 years ago
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kolezko [41]

Answer:

c

Explanation:

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3 years ago
A bus leaves at 9 am with a group of tourists. They travel 350 km before they stop for lunch. Then they travel an additional 250
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Average speed = Distance traveled / time taken

In this case Time taken = Difference in hours between 3 PM and 9 AM

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So the bus's average speed = 27.78 m/s or 100 km/hr.

8 0
3 years ago
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