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natima [27]
2 years ago
8

A student is studying a sample of carbon dioxide gas inside a small syringe. At constant temperature the syringe has a volume of

89. 6 ml at a pressure of 3. 00 atm. When the syringed is expanded to a volume of 215 ml, what is the new pressure inside the syringe?.
Chemistry
1 answer:
Soloha48 [4]2 years ago
4 0

The new pressure inside the syringe will be 1.25 atm

<h3>Gas law</h3>

At constant temperatures, the volume of a gas is inversely proportional to its pressure.

Thus:   P1V1 = P2V2

In this case, P1 = 3.0 atm, V1 = 89.6 mL, V2 = 215 mL

P2 = P1V1/V2

                         = 3 x 89.6/215

                              = 1.25 atm

More on gas laws can be found here: brainly.com/question/1190311

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Identify the neutralization reaction.
dusya [7]

The neutralization reaction among all the reactions would be the one between an acid and a base to produce salt and water.

<h3>What is a neutralization reaction?</h3>

It is a reaction involving an acid and a base to produce salt and water.

From the list of reactions, the only reaction that involves acid and a base with salt and water being the products is the first reaction.

Thus, the neutralization reaction is represented by the equation:

2H_3PO_4 + 3Ba(OH)_2 --- > 6H_2O + Ba(PO_4)_2

More on neutralization reactions can be found here: brainly.com/question/20038776

#SPJ1

4 0
2 years ago
Which of the following best describes the distribution of the world’s food supply? Select all that apply.
cupoosta [38]

Answer: It would be A and C

Explanation: I did the test and got it right. Hope this helps!

5 0
3 years ago
Read 2 more answers
Draw an orbital overlap diagram to represent the bonding in ammonia, NH3.
Svetlanka [38]
NH3 is a molecule with a nitrogen atom in the middle surrounded by 3 hydrogen atoms bonded covalently. Nitrogen has 5 valence electrons so, it will form sigma bonds (sp3 hybrid orbitals) with each of the hydrogen atom. The remaining lone pair electrons will be situated above the atom. You ca look at this image I've pulled from Google.

5 0
3 years ago
How do you determine if and ion has a<br> noble-gasconfiguration?
Soloha48 [4]

Explanation:

Noble gas configuration is defined as the configuration which contains completely filled orbitals.

For example, oxygen atom when gain two electrons then it forms oxygen ion (O^{2-}).

Atomic number of oxygen atom is 8 and so, its number of electrons will also be 8. But when it gain two electrons then it has total 10 electrons. Hence, electronic configuration of O^{2-} is as follows.

          1s^{2}2s^{2}2p^{6}

Since, there are completely filled orbitals in an O^{2-} ions. Therefore, it means this ion has a  noble-gas configuration.

Thus, we can conclude that any specie which shows completely filled orbitals will have noble-gas configuration.

3 0
4 years ago
(a) How many stereoisomers are possible for 4,4-dimethyl-1,2-cyclopentanediol?
Monica [59]

Answer:

(a) 4 stereoisomers: (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. (b) (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol (c) No, they are optically inactive.

Explanation:

(a) The stereoisomers possible for 4,4-dimethyl-1, 2-cyclopentanediol are (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. Their structures are shown in the attached file.

(b) The oxidation reaction that occurs between 4,4-dimethylcyclopentene and osmium tetroxide produces (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol. Their structures are also shown in the attached file.

(c) The products of the oxidation reaction in (b) are optically inactive because the compounds contain plane of symmetry that makes them optically inactive compound.

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5 0
4 years ago
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