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LuckyWell [14K]
3 years ago
12

The density of water is 1.00 g/ml at 4°c. how many water molecules are present in 2.36 ml of water at this temperature?

Chemistry
1 answer:
spin [16.1K]3 years ago
5 0

Mass of 1 ml of water 1 g as density of water 1.00 g/ml at 4° C. So, mass of 2.36 ml of water \frac{1}{2.36} g= 0.423 g.

Molecular mass of water is 18 g which indicates 18 g water contains 6.023 X 10^{23} number of water molecules. So, 0.423 g of water contains \frac{6.023 X 10^{23} X 0.423 }{18}  g = 0.141 X 10^{23} number of water molecules= 1.41 X 10^{22} number of water molecules.

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Explanation:

Given that,

Original volume of oxygen (V1) = 30.0L

Original temperature of oxygen (T1) = 200°C

[Convert temperature in Celsius to Kelvin by adding 273.

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New volume of oxygen V2 = ?

New temperature of oxygen T2 = 1°C

(1°C + 273 = 274K)

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

30.0L/473K = V2/294K

To get the value of V2, cross multiply

30.0L x 294K = 473K x V2

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3 years ago
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Arturiano [62]

The question is incomplete, the complete question is;

One tank of goldfish is feed the normal amount which is once a day, a second tank is fed twice a day, and a third tank is fed four times a day during a 6 week study. The fishes' body fat is recorded daily.

Independent Variable-

Dependent Variable-

Constants

Control Group-

Answer:

A) The amount of food the gold fish receives

B) Body fat of the gold fish

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Explanation:

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