All categories

3 years ago

How to convert 3.612 x 10^23 atoms Fe

Chemistry

1 answer:

andrezito [222]3 years ago

8 0

Answer:

0.599800731 moles or 33.4988708 grams

Explanation:

You are given the number of atoms. To convert to moles, divide by the number of atoms in a mole:

(3.612*10^23 atoms)/(6.022*10^23 atoms per mole) = 0.599800731 moles

Then, multiply the number of moles by the molar mass of Fe (iron).

(0.599800731 moles)*(55.85 grams per mole) = 33.4988708 grams

You might be interested in

Whats the simplest mole ratio of Oxygen? I'll give brainliest if you can help.

spayn [35]

Answer:

O: 3.41 / 3.41 = 1.00.

Explanation:

To find the simplest whole number ratio, divide each number by the smallest number of moles

3 0

3 years ago

Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4? Upper K upper O upper H right arrow upper H

sertanlavr [38]

Answer :

The balanced chemical reaction will be,

$H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

When sulfuric acid react with potassium hydroxide then it react to give potassium sulfate and water as a product. This reaction is known as acid-base reaction.

The balanced chemical reaction will be,

$H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

4 0

3 years ago

Read 2 more answers

The activation energy for a given reaction is 56 kj/mol. at what temperature would the rate constant be quadruple what is was at

Alex787 [66]

The rate equation is given as:

k = A e^(- Ea / RT)

Dividing state 1 and state 2:

k1/k2 = e^(- Ea / RT1) / e^(- Ea / RT2)

k1/k2 = e^[- Ea / RT1 - (- Ea / RT2)]

k1/k2 = e^[- Ea / RT1 + Ea / RT2)]

Taking the ln of both sides:

ln (k1/k2) = - Ea / RT1 + Ea / RT2

ln (k1/k2) = - Ea / R (1/T1 - 1/T2)

Since k2 = 4k1, therefore k1/k2 = ¼

ln (1/4) = [- (56,000 J/mol) / (8.314 J / mol K)] (1/273 K – 1/ T2)

2.058 x 10^-4 = 1/273 – 1/T2

T2 = 289.25 K

8 0

2 years ago

Reading the temperature of a solution by using a thermometer is an example of a(n) ________.

weeeeeb [17]

Answer:

i guess its example of observation

6 0

2 years ago

18. What is the density of a substance with a mass of 0.90 kg and a volume of 1.2 mL?

Anton [14]

Answer:

fffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff

Explanation:

4 0

3 years ago