Answer:
Explanation:
In Ptolemy's geocentric model of the universe, the Sun, the Moon, and each planet orbit a stationary Earth. He had them in circle orbits.
Galileo's model showed that the sun was the centre of the universe. That everything orbited around the earth. He also saw that they we in elliptical orbits.
Galileo proved Ptolemy wrong because Ptolemy said that everything orbited the earth and they orbited in circle but they orbit in ovals (elliptical) and that they orbit the sun.
Answer:
The distance is 2 cm
Solution:
According to the question:
Magnetic field of Earth, B_{E} = ![5.0\times 10^{- 5} T](https://tex.z-dn.net/?f=5.0%5Ctimes%2010%5E%7B-%205%7D%20T)
Current, I = 5.0 A
We know that the formula of magnetic field is given by:
![B = \farc{\mu_{o}I}{2\pi d}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfarc%7B%5Cmu_%7Bo%7DI%7D%7B2%5Cpi%20d%7D)
where
d = distance from current carrying wire
Now,
![d = \frac{\mu_{o}I}{2\pi B}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B%5Cmu_%7Bo%7DI%7D%7B2%5Cpi%20B%7D)
![d = \frac{4\pi\times 10^{- 7}\times 5.0}{2\pi\times 5.0\times 10^{- 5}}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B4%5Cpi%5Ctimes%2010%5E%7B-%207%7D%5Ctimes%205.0%7D%7B2%5Cpi%5Ctimes%205.0%5Ctimes%2010%5E%7B-%205%7D%7D)
d = 0.02 m 2 cm
Answer:
it would have to be 1 or maybe 2
a) 189.2 J
b) 13.5 W
Explanation:
a)
The work done by the force on the package is equal to the scalar product between force and displacement:
![W=F\cdot d](https://tex.z-dn.net/?f=W%3DF%5Ccdot%20d)
where F is the force and d is the displacement.
In this problem, the force is:
![F=(5.0)i+(6.0)j+(10.0)k[N]](https://tex.z-dn.net/?f=F%3D%285.0%29i%2B%286.0%29j%2B%2810.0%29k%5BN%5D)
We know the initial position:
![d_i=(0.6 m)i + (0.75 m)j + (0.28 m)k](https://tex.z-dn.net/?f=d_i%3D%280.6%20m%29i%20%2B%20%280.75%20m%29j%20%2B%20%280.28%20m%29k)
and the final position:
![d_f=(7.5 m)i + (15.0 m)j + (7.2 m)k](https://tex.z-dn.net/?f=d_f%3D%287.5%20m%29i%20%2B%20%2815.0%20m%29j%20%2B%20%287.2%20m%29k)
So, the displacement is the difference between the two positions:
![d=d_f-d_i=(7.5-0.6)i+(15.0-0.75)j+(7.2-0.28)k=\\=6.9i+14.25j+6.92k[m]](https://tex.z-dn.net/?f=d%3Dd_f-d_i%3D%287.5-0.6%29i%2B%2815.0-0.75%29j%2B%287.2-0.28%29k%3D%5C%5C%3D6.9i%2B14.25j%2B6.92k%5Bm%5D)
Therefore, the scalar product between force and displacement is:
![W=(5.0\cdot 6.9)+(6.0\cdot 14.25)+(10.0\cdot 6.92)=189.2 J](https://tex.z-dn.net/?f=W%3D%285.0%5Ccdot%206.9%29%2B%286.0%5Ccdot%2014.25%29%2B%2810.0%5Ccdot%206.92%29%3D189.2%20J)
b)
The average power of the machine is the rate of work done per unit time; it is given by
![P=\frac{W}{t}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7Bt%7D)
where
W is the work done
t is the time elapsed
In this problem, we have:
W = 189.2 J (work done)
t = 14.0 - 0 = 14.0 s (time elapsed)
Therefore, the average power of the machine is:
![P=\frac{189.2}{14}=13.5 W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B189.2%7D%7B14%7D%3D13.5%20W)