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Yuri [45]
3 years ago
5

The variables for part 1 of this experiment include the types of materials, used in the cup, the masses of these materials and t

heir temperatures over time. use the drop down menus to complete the sentences and identify the independent and dependent variables.
Chemistry
1 answer:
iVinArrow [24]3 years ago
8 0
So, first off let’s look at what an independent and dependent variable is.

an independent variable doesn’t change when other variables change, therefore making it alone and independent.

a dependent variable changes based on other variables.

so, i don’t have enough information on your experiment to know the answer but think to yourself, what is changing over time based on something else changing (dependent variable) or think does this thing stay the same no matter what (independent variable).

hope this helps!
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The deepest trench in the world is 11,000 m in depth. Assuming sea water to have a constant density of 1050 kg/m, determine the
Vanyuwa [196]

Answer:

113406825 N/m²

Explanation:

The pressure at depth of 11,000 m can be calculated by:

Pressure = Atmospheric pressure + Pressure  due to height

Atmospheric pressure = 101325 N/m²

Also,  

P_{height}=\rho\times g\times h

Where,  

\rho is the density of water (\rho=1050\ kg/m^3)

g is the gravitational acceleration = 9.81 m/s²

h = 11,000 m

P_{height}=1050\ kg/m^3\times 9.81\ m/s^2\times 11000\ m

Pressure  due to height = 113305500 N/m²

<u>Pressure = Atmospheric pressure + Pressure  due to height = 101325 N/m² + 113305500 N/m² = 113406825 N/m²</u>

5 0
3 years ago
Read 2 more answers
a ray in the emission spectrum has a wavelength of 3.10x10^14 meters. given that the speed of light is 2.998x10^8m/. what is the
Sloan [31]
The frequency of the ray with a wavelength of 3.10 × 10¹⁴  is 9.671 × 10⁻⁷.

I attached the working and the answer to the question below. I hope I was able to help.

Please note that C = speed of light, ν = frequency and λ= wavelength.

8 0
3 years ago
Revise sentence 2 by adding the correct pronoun.
Sidana [21]

Answer:

his, her

Explanation:

edginuity

3 0
3 years ago
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a certain anesthetic contains 64.9% C, 13.5% H, and 21.6% O by mass. at 120 deg Celsius &amp; 750 mmHg, 1.00 L of the gaseous co
slamgirl [31]
You need to use the % information to determine the empirical formula of the compound first. 

The empirical formula is the simplest ratio of atoms in the molecule. 

Then use the rest of the data to determine moles of gas, and use this to determine molar mass of gas... 

Empirical formula calculations:

Assume you have 100 g, calculate the moles of each atom in the 100 g 

moles = mass / molar mass 
molar mass C = 12.01 g/mol 
molar mass H = 1.008 g/mol 
molar mass O = 16.00 g/mol 

C = 64.9 % = 64.6 g 
H = 13.5 % = 13.5 g 
O = 21.6 % = 21.6 g 

moles C = 64.6 g / 12.01 g/mol = 5.38 mol 
moles H = 13.5 g / 1.008 g/mol = 13.39 mol 
moles O = 21.6 g / 16.00 g/mol = 1.35 mol 

So ratio of C : H : O 
is 5.38 mol : 13.39 mol : 1.35 mol 

Divide each number in the ratio by the lowest number to get the simplest whole number ratio 

(5.38 / 1.35) : (13.39 / 1.35) : (1.35 / 1.35) 

4 : 10 : 1 

empirical formula is 
C4H10O 


Finding moles and molar mass calcs 

Now, you know that at 120 deg C and 750 mmHg that 1.00L compound weighs 2.30 g. 

We can use this information to determine the molar mass of the gas after first working out how many moles the are in the 1.00 L 

PV = nRT 
P = pressure = 750 mmHg 
V = volume = 1.00 L 
n = moles (unknown) 
T = temp in Kelvin (120 deg C = (273.15 + 120) Kelvin) 
- T = 393.15 Kelvin 
R = gas constant, which is 62.363 mmHg L K^-1 mol^-1 (when your P is in mmHg and volume is in L) 

n = PV / RT 
n = (750 mmHg x 1.00 L) / (62.363mmHg L K^-1 mol^-1 x 393.15 K) 
n = 0.03059 moles of gas 

We know moles = 0.03509 and mass = 2.30 g 
So we can work out molar mass of the gas 

moles = mass / molar mass 
Therefore molar mass = mass / moles 
molar mass = 2.30 g / 0.03059 mol 
= 75.19 g/mol 


Determine molecular formula 

So empirical formula is C4H10O 
molar mass = 75.19 g/mol 

To find the molecular formula you divide the molar mass by the formula weight of the empirical formula... 
This tells you how many times the empirical formula fits into the molecular formula. Tou then multiply every atom in the empirical formula by this number 

formula weight C4H10O = 74.12 g/mol 

Divide molar mass by formula weight empirical 
75.15 g/mol / 74.12 g/mol 
= 1 
(It doesn't matter that the number don't quite match, they rarely do in this type of calc (although I could have made a slight error somewhere) but the numbers are very close, so we can say 1.) 

The empirical formula only fits into the molar mass once, 

molecular formula thus = empirical formula 
<span>
C4H10O

Therefore, the </span>molecular formula of the compound is <span>C4H10O.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
5 0
3 years ago
Which is the anode (oxidation) and cathode (reduction)?
arsen [322]

Answer:

2H+ + 2e - ---> H2(g) is the cathode

2Cl - ---> Cl2(g) + 2e - is the anode

Explanation:

Hydrogen ion has gained two electrons, making it undergo reduction. While chlorine has lose two electrons, hence undergoing oxidation.

8 0
3 years ago
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