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3 years ago

Need physics help! (there’s a picture)

Physics

1 answer:

Nezavi [6.7K]3 years ago

5 0

Answer:

i. Subtract v₀² from both of the equation.

ii. Divide both side of the equation by 2

iii. Divide both side of the equation by (x – x₀)

a = (v² – v₀²) / 2(x – x₀)

Explanation:

v² = v₀² + 2a(x – x₀)

To solve for a in the expression above, do the following:

i. Subtract v₀² from both of the equation.

v² – v₀² = v₀² – v₀² + 2a(x – x₀)

v² – v₀² = 2a(x – x₀)

ii. Divide both side of the equation by 2

(v² – v₀²) /2= 2a(x – x₀)/2

(v² – v₀²) /2 = a(x – x₀)

iii. Divide both side of the equation by (x – x₀)

(v² – v₀²) /2 ÷ (x – x₀) = a(x – x₀)/(x – x₀)

(v² – v₀²) /2 × 1/ (x – x₀) = a

a = (v² – v₀²) / 2(x – x₀)

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iren2701 [21]

Answer:

Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.

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3 years ago

A mustang, has an average velocity of 33 m/s while covering a course that is 21 miles long. (1 mile = 1609 m). How long did it t

saw5 [17]

Answer:

t = 1023.9 seconds

Explanation:

Given that,

The average velocity of a Mustang, v = 33m/s

Distance, d = 21 miles = 33789 m

Let the driver takes t seconds. So,

Speed = distance/time

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3 years ago

A metal has a strength of 414 MPa at its elastic limit and the strain at that point is 0.002. Assume the test specimen is 12.8-m

ser-zykov [4K]

To solve this problem, we will start by defining each of the variables given and proceed to find the modulus of elasticity of the object. We will calculate the deformation per unit of elastic volume and finally we will calculate the net energy of the system. Let's start defining the variables

Yield Strength of the metal specimen

$S_{el} = 414Mpa$

Yield Strain of the Specimen

$\epsilon_{el} = 0.002$

Diameter of the test-specimen

$d_0 = 12.8mm$

Gage length of the Specimen

$L_0 = 50mm$

Modulus of elasticity

$E = \frac{S_{el}}{\epsilon_{el}}$

$E = \frac{414Mpa}{0.002}$

$E = 207Gpa$

Strain energy per unit volume at the elastic limit is

$U'_{el} = \frac{1}{2} S_{el} \cdot \epsilon_{el}$

$U'_{el} = \frac{1}{2} (414)(0.002)$

$U'_{el} = 414kN\cdot m/m^3$

Considering that the net strain energy of the sample is

$U_{el} = U_{el}' \cdot (\text{Volume of sample})$

$U_{el} = U_{el}'(\frac{\pi d_0^2}{4})(L_0)$

$U_{el} = (414)(\frac{\pi*0.0128^2}{4}) (50*10^{-3})$

$U_{el} = 2.663N\cdot m$

Therefore the net strain energy of the sample is $2.663N\codt m$

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3 years ago

Tyler wants to learn about the types of insects in the soil near his house. Which would be a benefit of carrying out a descripti

lara31 [8.8K]

To gather more information and details on the soil

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3 years ago

Each year, an average person in the United States is exposed to a radiation level of _____.

Anna11 [10]

Answer:

The correct answer is 0,2 rems

Explanation:

People are exposed to natural sources of radiation all the time. According to recent estimates, the average person in the United States receives an effective dose of approximately 3 mSv per year of natural radiation, which is equivalent to 0.3 rems. This amount includes cosmic radiation from outer space and is average because it varies depending on the region people are in.

The amount of radiation for a chest x-ray of an adult (0.01 rems) is approximately equal to 10 days of natural radiation to which we are all exposed every day.

Have a nice day!

3 0

3 years ago