Answer:
Explanation:
Hello,
For the given chemical reaction:
We first must identify the limiting reactant by computing the reacting moles of Al2S3:
Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:
Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:
Finally, we compute the percent yield with the obtained 2.10 g:
Best regards.
Use the Henderson-Hasselbach equation:
pH = pKa + log[base]/[acid]
pH = -log(1.7 x 10^-5) + log(0.590/0.130) = 5.43
The answer is 2 more oxygen is needed
Answer:
C₆H₁₂O₆ and O₂
Explanation:
To know which option is correct, it important that we know the concepts of chemical equation .
A chemical equation gives us an expression of a chemical reaction in terms of symbols and formula. There are two sides to every equation. The side bearing the reactant and the side bearing the product.
The reactant is located on the left side and the product is located on the right side.
Reactant —> Product
With the above information, let us answer the question given above.
6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂
The products are located on the right side of the equation.
Thus, the products of the reaction is C₆H₁₂O₆ and O₂
