A 35.0 ml sample of 0.225 m hbr was titrated with 42.3 ml of koh. What is the concentration of the koh?
1 answer:
Answer:
The concentration of KOH is 0.186 M
Explanation:
First things first, we need too write out the balanced equation between HBr and KOH.
This is given as;
KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)
From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.
We use the acid base formular in calculating unknown concentrations. This is given as;
where;
Ca = Concentration of acid
Va = Volume of acid
Cb = Concentration of base
Vb = Volume of base
na = Number of moles of acid
nb = Number of moles of base
KOH is the base and HBr is acid.
Hence;
Ca = 0.225
Va = 35
Cb = ?
Vb = 42.3
na = 1
nb = 1
Making Cb subject of formular we have;
Cb = (0.225 * 35 * 1) / (42.3 * 1)
Cb = 0.186 M
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b) : acid
:conjugate base.
And, : base
: conjugate acid.
c)
d)
e)
Explanation:
a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases ions in their aqueous states.
The equation for the dissociation of acid is given by:
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For the given chemical equation:
is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
And, is gaining a proton, thus it is considered as a base and after gaining a proton, it forms
which is a conjugate acid.
c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.
d) The chemical equation for dissociation of in water.
e) The chemical equation for the reaction of and