214.746049. I converted between grams Manganese
Answer:
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Explanation:
First, calculate the number of moles of sodium present with the given mass,
31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium
It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.
mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2
Then, at STP, 1 mol of gas = 22.4 L.
volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L
Answer: 15.34 L
Answer:
![m_{HBO_2}=441.8gHBO_2](https://tex.z-dn.net/?f=m_%7BHBO_2%7D%3D441.8gHBO_2)
Explanation:
Hello there!
In this case, since the combustion of B2H6 is:
![B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O](https://tex.z-dn.net/?f=B_2H_6%2B3O_2%5Crightarrow%202HBO_2%2B2H_2O)
Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:
![m_{HBO_2}=139.5gB_2H_6*\frac{1molB_2H_6}{27.67gB_2H_6} *\frac{2molHBO_2}{1molB_2H_6} *\frac{43.82gHBO_2}{1molHBO_2}](https://tex.z-dn.net/?f=m_%7BHBO_2%7D%3D139.5gB_2H_6%2A%5Cfrac%7B1molB_2H_6%7D%7B27.67gB_2H_6%7D%20%2A%5Cfrac%7B2molHBO_2%7D%7B1molB_2H_6%7D%20%2A%5Cfrac%7B43.82gHBO_2%7D%7B1molHBO_2%7D)
![m_{HBO_2}=441.8gHBO_2](https://tex.z-dn.net/?f=m_%7BHBO_2%7D%3D441.8gHBO_2)
Best regards!
Answer:
How many moles of oxygen are in 2.71 x 1025 molecules of carbon dioxide (CO2)? 90 moles. How many moles are there in 125 grams of carbon? 10.42 moles of carbon.
Explanation: