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vfiekz [6]
3 years ago
13

PLEASE HELLLLOOPLPPPPP

Chemistry
2 answers:
Sindrei [870]3 years ago
6 0

Answer:

D: Class I think

vovangra [49]3 years ago
4 0

Answer:

the answer is d.Class there u go i hope its riht

You might be interested in
The concentration of an HCl acid solution is initially 6mol/L. What would the concentration of a new solution be if 200 mL of th
pochemuha

Taking into account the definition of dilution, the concentration of the new solution is 1 mol/L.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

<h3>Final volume</h3>

In this case, you know:

  • Ci= 6 mol/L
  • Vi= 200 mL
  • Cf= ?
  • Vf= 1 L (1000 mL) water + 200 mL of HCL= 1200 mL

Replacing in the definition of dilution:

6 mol/L× 200 mL= Cf× 1200 mL

Solving:

(6 mol/L× 200 mL)÷ 1200 mL= Cf

<u><em>1 mol/L= Cf</em></u>

In summary, the concentration of the new solution is 1 mol/L.

Learn more about dilution:

brainly.com/question/6692004

brainly.com/question/16343005

brainly.com/question/24709069

#SPJ1

5 0
1 year ago
Sodium electron configuration in longhand notation
Elden [556K]

Answer:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

Explanation:

Sodium is present in group 1.

It is alkali metal.

It has one valence electron.

The atomic number of sodium is 11.

Its atomic mass is 23 amu.

The longhand notation of electronic configuration of sodium can be written as,

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

The electronic configuration in shorthand notation( noble gas) would be written as,

Na₁₁ = [Ne] 3s¹

Sodium loses its one valence electron to complete the octet and get stable thus form +1 cation.

It react with halogen and form salt. Such as sodium chloride.

2Na + Cl₂  →  2NaCl

5 0
3 years ago
What is the mass of air in room
tigry1 [53]

Answer:

the mass of the air in the room is 4.96512 kg ( in 0°C)

3 0
2 years ago
Please help me I have not gone over this in like 8 months and can not remember how to do it
Leona [35]

Answer:

91%

Explanation:

Since you are just trying to find the yield, take the moles of the substance from the products and divide it by the mol value of the reactants. Multiply by 100 to find percentage

0.45 ÷ 0.41 = 0.91111...

91%

4 0
3 years ago
what is the maximum amount of moles of P2O5 that can theoretically be made from 136 g of P4 and excess oxygen
zhuklara [117]
We are given with
136 g P4
excess oxygen

The complete combustion reaction is
P4 + 5O2 => 2P2O5
Converting the amount of P4 to moles
136/123.9 = 1.098 moles

Using stoichiometry
moles P2O5 = 1.098 x 2 = 2.195 moles P2O5
6 0
3 years ago
Read 2 more answers
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