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Rufina [12.5K]
3 years ago
11

3. Hypothesize Earth systems interact with

Chemistry
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

hi sorry

Explanation:

none

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If an atom has an atomic number of 6 and and abdomens mass of 12 how many electrons does it have
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Atomic number refers to the proton number of the atom itself. Number of electrons in an atom (an atom that is not reacted with any other molecules / Just the atom alone), is the same as the number of protons, because each electron has 1 negative charge, and each proton 1 positive charge, where they cancel out on each other to become a neutral charge.

So, when atomic number is 6, proton number is also 6, and number of electrons will also be 6 in that atom.

Hope this helps! :)
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5 0
3 years ago
Determine the empirical formula of a compound containing 24.74% potassium, 34.74% manganese, and 40.50% oxygen. What is the name
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The standard state of mercury
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Explanation:

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3 0
3 years ago
Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.60ft.
garik1379 [7]

<u>Given:</u>

Dimensions of the room= 12 ft * 15 ft * 8.60 ft

<u>To determine:</u>

The amount of HCN that gives the lethal dose in the room with the given dimensions

<u>Explanation:</u>

As per the World Health Organization, the lethal dose of HCN is around 300 ppm

300 ppm = 300 mg of HCN/ kg of inhaled air

Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³

Now,  1 ft³ = 28316.8 cm³

Therefore, the calculated volume of air corresponds to:

1548 * 28316.8 = 4.383 * 10⁷ cm3

Density of air (at room temperature 25 C) = 0.00118 g/cm3

Thus mass of air corresponding to the calculated volume is

Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3

= 5.172*10⁴ g = 51.72 kg

Lethal amount of HCN corresponding to 51.72 kg of air would be.

= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg

Ans: Lethal dose of HCN = 15.5 g

7 0
3 years ago
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