I'm assuming you need to know the percentage yield of the reaction
To calculate the percentage yield = (actual yield x 100%) / predicted yield
actual yield is 56,9 g
predicted yield is 36,6g ( is the amount that's expected if nothing had got lost)
(56,9 x100)/36,6=
= 155%
Only 1 molecule of NH3 will be produced in the following reaction since it requires 2 moles of nitrogen and excess hydrogen to create one molecule. We can't create more than one since we only have 1 of the nitrogen molecule remaining.
Answer:
6H20 represents six molecules of water