The fulcrum of a uniform 20-kg seesaw that is 4.0 m long is located 2.5 m from one end. A 30-kg child sits on the long end. Part
A Determine the mass a person at the other end would have to be in order to balance the seesaw. Express your answer to two significant figures and include the appropriate units. m = nothing nothing
1 answer:
Answer:
57 kg
Explanation:
Mass of seesaw = 20 kg
Length of seesaw = 4 m
Mass of child on the longer end = 30 kg
The weight of the seesaw acts at the center i.e. 2m
The algebraic sum of moments of all forces about any point is zero, hence, using the fulcrum as the reference point:
[x * 9.8* 1.5] - [20 * 9.8* (2.5 - 2)] - [30 * 9.8 * 2.5] = 0
=> 14.7x = (20*9.8*0.5) + 735
14.7x = 98 + 735
14.7x = 833
=> x = 833/14.7
x = 57 kg
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Answer:
B = 0.129 T
Explanation:
Given,
frequency, f = 60 Hz
maximum emf = 5200 V
Number of turns, N = 130
Area per turn = 0.82 m²
We know,
ω = 2 π f
ω = 2 π x 60 = 376.99 rad/s
now, Magnetic field calculation
B = 0.129 T
Hence, the magnetic field is equal to B = 0.129 T
Answer:
mass = 9.7 kg
Explanation:
As we know that when object is at rest on the ground of flat base then we will have
so from here
now we have
N = 95 Newton
now from above equation we will have