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sashaice [31]
3 years ago
8

How does the vertical component of a pro- jectile’s motion compare with the motion of vertical free fall when air resistance is

negligi- ble?
Physics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

Explanation:

In case of projectile motion, the acceleration acts is in vertical direction only which is due to the acceleration due to gravity.

In case of free fall the body moves along the vertical straight line, which is again under the acceleration due to gravity. Thus the motion of a body under free fall and the vertical  motion of a projectile is same.

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for every 120 joules of energy input a car waste 85 joules, find the useful energy output of the car?
harina [27]

Answer:

Useful Output = 35 J

Explanation:

The useful energy output of the car must be equal to the difference between the total input energy supplied to the car and the energy wasted by the car:

Useful Output = Total Input - Waste

where,

Total Input = 120 J

Waste = 85 J

Therefore,

Useful Output = 120 J - 85 J

<u>Useful Output = 35 J</u>

7 0
3 years ago
Change into60f into c​
Reil [10]

Answer:

15.6 C

Explanation:

Here we are given a temperature in Fahrenheit (F). We want to convert it into Celsius degrees (C).

The conversion can be done by using the following equation:

T(C)=\frac{5}{9}(T(F)-32)

where

T(C) is the temperature in Celsius degrees

T(F) is the temperature in Fahrenheit degrees

In this problem, we have

T(F) = 60 F

Therefore, by applying the equation,

T(C)=\frac{5}{9}(60-32)=15.6 C

8 0
3 years ago
27. Calculate the impulse when an average<br> force of 10 N acts on a cart for 5.0 s.
wlad13 [49]

Answer:

50 Ns

Explanation:

Impulse = force × time

J = F Δt

J = (10 N) (5.0 s)

J = 50 Ns

6 0
4 years ago
If a rat with a mass of 2.67 kg is being held at a height of 4.83 m, what is its potential energy?
Rom4ik [11]

Answer:

128.96J

Explanation:

Take g = 10m/s²

Ep = mgh

= 2.67 × 10 × 4.83 = 128.96 J

7 0
3 years ago
A 55-kg mountain climber, starting from rest, climbs a vertical distance of 701 m. At the top, she is again at rest. In the proc
aksik [14]

Answer:

7.75%

Explanation:

mass of climber, m = 55 kg

height, h = 701 m

Qc = 4.5 x 10^6 J (heat exhaused by the body)

Work = m x g x h

W = 55 x 9.8 x 701

W = 377839 J

W = QH - Qc

Where, QH is the heat input

QH = 377839 + 4.5 x 10^6

QH = 4877839 J

So, the efficiency

e = W / QH

e = 377839 / 4877839

e = 0.0774 = 7.75 %

Thus, the efficiency of the body is 7.75 %.

3 0
3 years ago
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