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Romashka [77]
3 years ago
15

PLEASE HELP!!!

Chemistry
2 answers:
IrinaVladis [17]3 years ago
6 0
Hi the answer is 100x I hope that helps
cestrela7 [59]3 years ago
4 0

Answer:

Magnifying power = 25

Explanation:

Magnification power (M) of a telescope is a measure of the extent to which it enlarges the object under view. It given in terms of the ratio of the focal length of the telescope objective to that of the eyepiece

M = \frac{objective\ focal\ length}{eyepiece\ focal\ length}-----(1)

The f/ratio measures the light gathering power of a lens. It is expressed in terms of the focal length of the lens divided by its diameter.

f/ratio = \frac{focal\ length}{diameter} ------(2)

It is given that:

eyepiece focal length = 2-inch

f/ratio = 10

Diameter of the objective = 5-inch

Based on eq(2), the focal length of the objective would be:

focal\ length = f/ratio * diameter = 10*5 = 50\ inches

Based on eq(1), the magnifying power would be:

M = \frac{50}{2} = 25

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Which ionic compound is the most likely to dissolve in water?
lbvjy [14]
The ionic compound is CaSO4
3 0
3 years ago
A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

7 0
3 years ago
How are flagella and cilia alike?
Hoochie [10]

Answer: Both store of celluar materials

Explanation:

I have the same question here is proof:

3 0
2 years ago
(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g
Schach [20]

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

5 0
3 years ago
BRAINLIESTTT ASAP!! PLEASE HELP ME :)
AlladinOne [14]

Answer : False, there will be two lithium and one oxygen atoms in a unit molecular structure of lithium oxide.

Explanation:

Electronic configuration of lithium is :

Li=1s^2s^1

In order to attain stable electronic configuration it will loose an electron and form positively charge cation.

Li^+=1s^22s^0

The electronic configuration of oxygen is:

O=1s^22s^22p^4

Oxygen being second most electronegative atom requires two electrons to attain noble gas configuration stability and form negatively charge ion with 2- charge.:

O^{2-}=1s^22s^22p^6

When two atom of lithium and oxygen comes together , one electron from each lithium atom get transferred to an oxygen atom which results in formation of lithium oxide.

2Li^++O^{2-}\rightarrow Li_2O

4 0
3 years ago
Read 2 more answers
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