All categories

2 years ago

Given a 240.0 g sample of sulfur trioxide (MM = 80.1 g/mol),

Chemistry

1 answer:

labwork [276]2 years ago

8 0

Answer:

2 mol of SO3 produces 1 mol O2

3 mol SO3 produces 3/2 mol of O2

so O2 produced = 1.5(32) =48 gm

Explanation:

You might be interested in

Consider the reaction 2CO(g) + O2(g)2CO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

Marizza181 [45]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(CO_2(g))})]-[(1\times \Delta S^o_{(O_2(g))})+(2\times \Delta S^o_{(CO(g))})]$

We are given:

$\Delta S^o_{(CO_2(g))}=213.74J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(CO)}=197.674J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (213.74))]-[(1\times (205.14))+(2\times (197.674))]\\\\\Delta S^o_{rxn}=-173.008J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-173.008) J/K = 173.008 J/K

We are given:

Moles of CO gas reacted = 2.25 moles

By Stoichiometry of the reaction:

When 2 moles of CO is reacted, the entropy change of the surrounding will be 173.008 J/K

So, when 2.25 moles of CO is reacted, the entropy change of the surrounding will be = $\frac{173.008}{1}\times 2.25=432.52J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

3 0

3 years ago

What is sewageband dirty amd water

Sav [38]

Answer:

Sewage is a liquid containing wastes from households, industrial and agricultural activities discharged into water and it is dirty water.

7 0

2 years ago

Absolute zero is A. the temperature at which the motion of particles theoretically ceases. B. defined as 0°C. C. the triple poin

Romashka-Z-Leto [24]

Absolute zero is the temperature at which the motion of particles that constitute heat will be minimal. The answer is A. It is the lowest temperature that is theoretically possible. It is zero on the kelvin scale, but equivalent to -273.15°C. Hope i helped.

7 0

3 years ago

Read 2 more answers

In which pair is each substance a mixture?

qaws [65]

Answer:

Air & Water

Explanation:

Air and water is the common mixtures in the book of the book called "Science & Land"

6 0

2 years ago

If the point of the nail can be approximated as a circle with a radius 2.00×10^-3m What is the pressure in MPa exerted on the wa

Natasha_Volkova [10]

Answer:

8.28 MPa

Explanation:

From the question given above, the following data were obtained:

Radius (r) = 2×10¯³ m

Force applied (F) = 104 N

Pressure (P) =?

Next, we shall determine the area of the nail (i.e circle). This can be obtained as follow:

Radius (r) = 2×10¯³ m

Area (A) of circle =?

Pi (π) = 3.14

A = πr²

A = 3.14 × (2×10¯³)²

A = 3.14 × 4×10¯⁶

A = 1.256×10¯⁵ m²

Next, we shall determine the pressure. This can be obtained as follow:

Force applied (F) = 104 N

Area (A) = 1.256×10¯⁵ m²

Pressure (P) =?

P = F / A

P = 104 / 1.256×10¯⁵

P = 8280254.78 Nm¯²

Finally, we shall convert 8280254.78 Nm¯² to MPa. This can be obtained as follow:

1 Nm¯² = 1×10¯⁶ MPa

Therefore,

8280254.78 Nm¯² = 8280254.78 Nm¯² × 1×10¯⁶ MPa / 1 Nm¯²

8280254.78 Nm¯² = 8.28 MPa

Thus, the pressure exerted on the wall is 8.28 MPa

3 0

3 years ago