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Taya2010 [7]
4 years ago
5

How many moles of N are in 0.173 g of N2O?

Chemistry
1 answer:
krok68 [10]4 years ago
3 0
Find the RMM of both then cross multiply keeping 0.173 under N2O and you will get the answer
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If a 28.0 L balloon with a temperature of
Alexeev081 [22]

Answer:

5.6 L

Explanation:

We can apply Charles' Law here since our pressure is constant (will not change inside the refrigerator) and we are relating change in volume with change in temperature:

V₁ / T₁ = V₂ / T₂ where V₁ and T₁ are initial volume and temperature, and V₂ and T₂ are final volume and temperature. Let's plug in what we know and solve for the unknown:

28.0 L / 25 °C = V₂ / 5 °C => V₂ = 5.6 L

5.6 L is our new volume (at 5 °C).

6 0
3 years ago
How many bonds would be needed when bonding 2 atoms of nitrogen to achieve a full octet for both atoms?
andriy [413]

Answer:

3 bonds are needed.

Explanation:

The electrons that are involved in chemical bonding are those in the outer shell of the highest energy level of the atom. The electron configuration of nitrogen (N) is 1s²2s²2p³. That means thy at each nitrogen atom has 5 valence electrons: 2 electrons in the 2s orbital and 3 electrons in the 2p orbital. To fullfil the octet, each nitrogen atom needs 3 electrons. So, they can share each other 3 electrons to form 3 simple bonds. Therefore, the nitrogen molecule (N₂) has 3 bonds involving 6 bonding electrons or a triple bond.

8 0
3 years ago
Calculate the number of ammonia molecules in 3.9 g.
disa [49]
•3.9g of ammonia
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1st you have to covert grams to moles by dividing the mass of ammonia with the molar mass:

(3.9 g)/ (17.03g/mol) = 0.22900763mols

Then convert the moles to molecules by multiplying it with Avogadro’s number:

Avogadro’s number: 6.022 x 10^23


0.22900763mols x (6.022 x 10^23 molecs/mol)
= 1.38 x 10^23 molecules
6 0
3 years ago
_____ chemical reactions need a certain amount of activation energy to get started.
Anettt [7]

Answer:all

Explanation:

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3 years ago
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Ion is an atom or molecule with a net electric charge due to loss or gain of one or more electrons.
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