How many moles of N are in 0.173 g of N2O?

Given LiCl, NaCl, KCl, MgCl2, and SrCl2, arrange the compounds in order of increasing lattice energy.

Oksanka [162]

Answer:- $KCl$

Explanations:- Lattice energy depends on two factors, charge and size.

High charge and small size gives higher lattice energy where as low charge and bigger size gives lower lattice energy.

in LiCl, NaCl and KCl, the anion is same and also the charges for Li, Na and K are also same. The deciding factor here is the size of cations. Since the size increases as we move down a group, the order of size of these three atoms is Li<Na<K.

The order of lattice energy is exactly opposite as it's increases as the size decreases.

Now, if we look at magnesium chloride and strontium chloride then again the anion is common but the metals have higher charge as compared to the alkali metals(Li, Na and K). So, lattice energy values must be higher for these two compounds. If we compare Mg and Sr then size of Mg is smaller and so the lattice energy would be greater for this.

Hence, the increasing order of lattice energy is $KCl$ .

4 0

2 years ago

Read 2 more answers

What sample has particles with the lowest average kinetic energy

makvit [3.9K]

The sample with the lowest AVERAGE kinetic energy is
the coolest one.

The sample with the lowest TOTAL kinetic energy depends on
not only the temperature of the samples, but also on their size,
since each molecule in the sample has kinetic energy.

5 0

2 years ago

The following reaction shows the products when sulfuric acid and aluminum hydroxide react.

Elden [556K]

The correct answer is approximately 11.73 grams of sulfuric acid.

The theoretical yield of water from Al(OH)3 is lower than that of H₂SO₄. As a consequence, Al(OH)3 is the limiting reactant, H₂SO₄ is in excess.

The balanced equation is:

2Al(OH)₃ + 3H₂SO₄ ⇒ Al₂(SO₄)₃ + 6H₂O

Each mole of Al(OH)3 corresponds to 3/2 moles of H₂SO₄. The molecular mass of Al(OH)3 is 78.003 g/mol. There are 15/78.003 = 0.19230 moles of Al(OH)3 in the five grams of Al(OH)3 available. Al(OH)3 is in limiting, which means that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.

The molar mass of H₂SO₄ is 98.706 g/mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.706 = 28.289 g

40 grams of sulfuric acid is available, out of which 28.289 grams is consumed. The remaining 40-28.289 = 11.711 g is in excess, which is closest to the first option, that is, 11.73 grams of H₂SO₄.

6 0

2 years ago

Choose a likely identity for X, Y, and Z in these structures. A central X atom is bonded to two chlorine atoms through single bo

natka813 [3]

Complete Question

The complete question is shown on the first uploaded image

Answer:

X is Be

Y is B

Z is O

Explanation:

In order to understand the solution, we need to that the an element form a bond based on

1 The number of valence electron available in its atom

2 The number of electron it require to attains its stable state i.e its Octet state

The number of valence electron for each of the option are

F = 7, N = 5 , O = 6 , C = 4 , B = 3 , Be = 2

Considering the first element

We see that X is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state

Now looking option we can see that Be has two valence electron in it atom and in order for it to attain its stable state it needs to release the electron so the correct option for this question is Be

Considering the second element

We see that Y is donating three valence electron in its atom and it is donating it to 3 Cl as Cl only requires a single electron to achieve its stable state

Now looking option we can see that B has three valence electron in it atom and in order for it to attain its stable state it needs to release the valence electron so the correct option for this question is B

Considering the second element

We see that Z is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state, also Z has 2 lone-pair valence electron

Now looking at the option we can see that O has 6 valence electron so if it donates 2 valence electron it will still be left with 4 - pair of electron

Therefore the correct option to this question is O

6 0

2 years ago

Explain why the C―Ha bond is much more acidic than the C―Hb bond in pentan-2-one. Select the single best answer. 253 Ha is less

mafiozo [28]

Answer:

Ha is more acidic than Hb because loss of Ha forms a resonance-stabilized conjugate base.

Explanation:

The carbon atom that is next to the carbonyl group in pentan-2-one is known as the alpha carbon atom, this carbon atom bears the Ha, the alpha hydrogen atoms.

Ha is more acidic than Hb because, loss of Ha leads to the formation of a resonance stabilized enolate ion. This resonance stabilization of the ion formed makes loss of Ha an easier process than loss of Hb, hence the answer above.

3 0

2 years ago