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netineya [11]
3 years ago
10

What is one reason that scientists who study weather need extremely advanced technology?

Chemistry
2 answers:
Anton [14]3 years ago
5 0

Answer: C) To monitor weather event restricted several days in advance.

Explanation:

Dovator [93]3 years ago
4 0
3)to monitor weather events restricted to one region
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A block has a mass of 325g and a volume of 500mL. What is its density? If water has a density (D=m/v) of 1g/mL, will the block f
Licemer1 [7]

Answer:

A. 0.65g/mL, float

Explanation:

Mass: 325g

Volume: 500mL

D = m/v

D = 325/500

D = 0.65

Therefore, the block has a density of 0.65g/mL and it will float since the density of water is greater than the density of the block.

4 0
4 years ago
WILL MARK BRAINLIEST !!!The variables for this experiment include temperature, surface area, and the time required for the react
DedPeter [7]
The independent variables, the ones that are intentionally manipulated, are

A) temperature and surface area



The dependent variable, the one that you measure the response in, is

C) reaction time .
4 0
4 years ago
Read 2 more answers
What is the charge of an ion that contains 21 protons and 19 electrons?
Nikolay [14]
1 proton = 1 positive charge
1 electron = 1 negative charge

+21-19= <u>+3</u>
5 0
3 years ago
A balloon contains 146.0 mL of gas confined at a pressure of 1.30 atm and a temperature of 5.0°C. If the pressure doubles and th
Komok [63]

Answer:

<u>72.2 mL</u>

Explanation:

Here values of Volume (V), Pressure (P), and Temperature (T) are given : <u>before</u> and <u>after</u>.

<u>Equating LHS (before) to RHS (after)</u>

  • P₁V₁/T₁ = P₂V₂/T₂
  • V₂ = P₁V₁T₂/T₁P₂
  • V₂ = 1.3 × 146 × 275 / 278 × 2.6
  • V₂ = 73 x 275 / 278
  • V₂ = <u>72.2 mL</u>
4 0
3 years ago
A 25.00 mL aliquot of concentrated hydrochloric acid (11.7M) is added to 175.00 mL of 3.25M hydrochloric acid. Determine the num
BlackZzzverrR [31]

Answer:

The number of moles of hydrochloric acid are 0.861

Explanation:

In first solution, the [HCl] is 11.7 M, which it means that 11.7 moles are present in 1 liter.

So we took 25 mL and we have to know how many moles, do we have now.

1000 mL ____ 11.7 moles

25 mL _____ (25 . 11.7)/1000 = 0.2925 moles

This are the moles, we add to the solution where the [HCl] is 3.25 M

In 1000 mL __ we have __ 3.25moles

175 mL ____ we have __ (175 . 3.25)/1000 = 0.56875 moles

Total moles: 0.2925 + 0.56875 = 0.861 moles

5 0
3 years ago
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