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netineya [11]
3 years ago
10

What is one reason that scientists who study weather need extremely advanced technology?

Chemistry
2 answers:
Anton [14]3 years ago
5 0

Answer: C) To monitor weather event restricted several days in advance.

Explanation:

Dovator [93]3 years ago
4 0
3)to monitor weather events restricted to one region
You might be interested in
Which solution is the best conductor of electric
nadezda [96]

(C) 0.1 mole of NaCl dissolved in 1,000. mL of water

<u>Explanation:</u>

The conductivity of 0.1 mole of NaCl dissolved in 1000 mL of water will be greatest as the number of ions in 0.1 mole of NaCl will be more than 0.001, 0.05 and 0.005 moles of NaCl. Greater the number of ions in the solution, greater will be the conductivity. Specific Conductivity decreases with a decrease in concentration. Since the number of ions per unit volume that carry current in a solution decrease on dilution. Hence, concentration and conductivity are directly proportional to each other.

4 0
3 years ago
How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?
Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

C_{6}H_{8}O_{6}

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g

To know the percent of each element, we need to to the following:

C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0
3 years ago
Which part of a chemical formula indicates the number of copies of molecules or compounds? A. plus signs B. subscripts C. coeffi
nadya68 [22]
I think it is C. coefficients but I don't know what subscripts are
3 0
4 years ago
The table shows the total number of electrons in Atom A and Atom B. Atom Number of Electrons A 10 B 18 Which statement is correc
HACTEHA [7]

Answer:

Both A and B will be unreactive!

Explanation:

10=2, 8

18=2, 8, 8

4 0
3 years ago
Read 2 more answers
Draw the structure of 1,4-hexanediamine.
brilliants [131]

Answer:

1,4-hexanediamine contains two -NH_{2} functional groups.

Explanation:

1,4-hexanediamine is an organic molecule which contains two -NH_{2} functional groups at C-1 and C-4 position.

The longest carbon chain in 1,4-hexanediamine contains six carbon atoms.

Molecular formula of 1,4-hexanediamine is C_{6}H_{16}N_{2}.

1,4-hexanediamine used as a bidentate ligand in organometallic chemistry.

The structure of 1,4-hexanediamine is shown below.

5 0
3 years ago
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