Answer:
670.68°C
Explanation:
Given that:
volume of water = 50 ml but 1 g = 1 ml. Therefore the mass of water (m) = 50 ml × 1 g / ml = 50 g
specific heat (C) = 4.184 J/g˚C
Initial temperature = 20°C, final temperature = 22°C. Therefore the temperature change ΔT = final temperature - initial temperature = 22 - 20 = 2°C
The quantity of heat (Q) used to raise the temperature of a body is given by the equation:
Q = mCΔT
Substituting values:
Q = 50 g × 4.184 J/g˚C × 2°C = 418.4 J
Since the mass of lead = 5 g and specific heat = 0.129 J/g˚C. The heat used to raise the temperature of water is the same heat used to raise the temperature of lead.
-Q = mCΔT
-418.4 J = 5 g × 0.129 J/g˚C × ΔT
ΔT = -418.4 J / ( 5 g × 0.129 J/g˚C) = -648 .68°C
temperature change ΔT = final temperature - initial temperature
- 648 .68°C = 22°C - Initial Temperature
Initial Temperature = 22 + 648.68 = 670.68°C
Ammonia yields nitric oxide and water in the presence of oxygen. The mass of nitric acid that will be produced from 6.40 gm of oxygen is 4.8 grams.
<h3>What is mass?</h3>
Mass is the product of the moles of the substance and its molar mass. it is given as,
The balanced chemical reaction is shown as:
Moles of oxygen are calculated by mass, 6.40 gm as,
From the reaction, the molar ratio of nitric oxide to oxygen is 4: 5 and is used to calculate the moles of nitric oxide as,
0.16 moles and molar mass, 30 of nitric oxide is used to calculate the mass as,
Therefore, 4.8 grams of nitric oxide will be produced.
Learn more about mass here:
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