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Ludmilka [50]
3 years ago
10

What is the mass of 2.49 moles of sucrose?

Chemistry
1 answer:
Andrews [41]3 years ago
6 0

your anwser would be 342 gmol  Please mark branliest

Just get out that Periodic Table of the Elements, find the atomic masses for each atom, and add them up!

Carbon = 12

Hydrogen = 1

Oxygen = 16

C=12×12=144

H=1×22=22

O=16×11=176

Sucrose =144+22+176=342gmol

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What is the molarity of a 0.25-liter solution containing 52 grams of HBr? (1 point)
Pani-rosa [81]

2.6 M hBr

This would be the correct answer.

3 0
3 years ago
How many molecules in 11 grams of CO2?
yawa3891 [41]

Answer:

1095.62

Explanation:

5 0
3 years ago
Help me clarify please!
zaharov [31]

Answer:

Round to the number of significant figures in the original question. However, if you're going to proceed with further calculations using this mass, it's best not to round, as rounding will cause your answer to be less precise.

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7 0
2 years ago
At 100 degrees Celsius, the ion product for pure water is Kw= 51.3*10^-14. What is the pOH of water at this temperature? A) 7.00
Levart [38]

7.86 is the pOH of water at this temperature of 100 degrees celsius.

Option E is the right answer.

Explanation:

Data given:

Kw = 51.3 x 10^{-14}

pOH = ?

we know that pure water is neutral and will have pH pf 7.

The equation for relation between Kw and H+ and OH- ion is given by:

Kw = [H+] [OH-}

here the concentration of H+ ion and OH- ion is equal

so, [H+]= [OH-]

Putting the values in the equation of Kw

pKw = -log[Kw]

pKw = -log [51.3 x 10^{-14}]

pKw = 12.28

since H+ ion OH ion concentration is equal the pH of water is half i.e. 6.14

Now, pOH is calculated by using the equation:

14 = pOH + pH

14- 6.14 = pOH

pOH = 7.86

8 0
3 years ago
Calculate the amount of heat water absorbs from a piece of hot metal using the following data: 75.0 g of cold water is placed in
AysviL [449]

Answer:

Amount of heat absorbed by water is 2604.54 J.

Explanation:

Amount of heat absorbed by water = m_{water}\times C_{water}\times \Delta T_{water}

where m represents mass, C represents specific heat and \Delta T represents change in temperature.

Here m_{water}=75.0 g , C_{water}=4.184J/(g.^{0}\textrm{C}) and \Delta T = (final temperature - initial temperature) = (29.5-21.2) ^{0}\textrm{C} = 8.3 ^{0}\textrm{C}

So, amount of heat heat absorbed by water

     = (75.0g)\times (4.184\frac{J}{g.^{0}\textrm{C}})\times (8.3^{0}\textrm{C})

     = 2604.54 J

8 0
3 years ago
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