Can you be more specific v
PbCl₂ ⇄ Pb²⁺ + 2 Cl⁻
Initially 0 5.4 M
Change -x + x + 2x
Equilibrium x 5.4 + 2x
Ksp = [Pb²⁺] [Cl⁻]²
1.6 x 10⁻⁵ = x (5.4 + 2x)²
since x <<<< 5.4 so 2x + 5.4 = 5.4
1.6 x 10⁻⁵ = x (5.4)²
x = 5.48 x 10⁻⁷
[Pb²⁺] = 5.48 x 10⁻⁷ M
Answer:
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