Answer:
Explanation:
1)
Given data:
Initial volume = 2.5 L
Initial temperature = 300 k
Final temperature = 80 k
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 2.5 L × 80 K / 300 k
V₂ = 200 L.K / 300 K
V₂ = 0.67 L
2)
Given data:
Initial volume = 752 mL
Initial temperature = 25.0°C (25+273 = 298 K)
Final temperature = 50.0°C(50+273 = 323 K)
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 752 mL × 323 K / 298 k
V₂ = 242896 mL.K / 298 K
V₂ = 815.1 mL
3)
Given data:
Initial volume = 2.75 L
Initial temperature = 20°C (20+273 = 293 K)
Final temperature = ?
Final volume = 2.46 L
Solution:
The given problem will be solve through the Charles Law.
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁
T₂ = 2.46 L × 293 K / 2.75 L
T₂ = 720.78 L.K / 2.75 L
T₂ = 262.1 K
4)
Given data:
Initial volume = 1500 L
Initial temperature = 5°C (5+273 = 278 K)
Final temperature = 30 °C(30+273 = 303 K)
Final volume of heated air = ?
Solution:
The given problem will be solve through the Charles Law.
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 1500 L × 303 K / 278 k
V₂ = 454500 L.K / 278 K
V₂ = 1634.89 L
5)
Given data:
Initial volume = 15.5 L
Initial temperature = 20°C (20+273 = 293 K)
Final temperature = 7.0 °C(7.0+273 = 280 K)
Final volume of balloon = ?
Solution:
The given problem will be solve through the Charles Law.
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 15.5 L × 280 K / 293 k
V₂ = 4340 L.K / 293 K
V₂ = 14.8 L
6)
Given data:
Initial volume = 150 mL
Initial temperature = 23.5°C (23.5+273 = 296.5 K)
Final temperature = 72.5 °C(72.5+273 = 345.5 K)
Final volume of balloon = ?
Solution:
The given problem will be solve through the Charles Law.
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 150 mL × 345.5 K / 296.5 k
V₂ = 51825 mL.K / 296.5 K
V₂ = 174.79 mL