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yaroslaw [1]
2 years ago
9

How do you give someone branily if only one person answered

Chemistry
2 answers:
Alex777 [14]2 years ago
8 0

Answer:

U cant thats the thing

Explanation:

Theres gotta be more than 1 person :)

neonofarm [45]2 years ago
3 0

Answer:

You have to wait until two people answer.

Explanation:

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Cómo puedes medir un gas?
Dima020 [189]
El gas se puede medir por volumen en cm3 utilizando un instrumento conocido como eudiómetro.
4 0
2 years ago
Which elements have atoms that are likely to form an anion?
KengaRu [80]
Answer:

Phosphorus, chlorine and selenium.

Explanation:

If you look at a periodic table, you will notice that phosphorus, chlorine and selenium are all in groups 15-17. Elements in these groups are more likely to gain electrons then they are to lose them, thus making them more likely to form an anion.
This is because they want to fill their outer valence shell of electrons so that they can have a full octet and for groups 15-17 it’s easier to gain 1-3 electrons then it is to loose 5-7 electrons.
5 0
3 years ago
Can you help me please ​
Mice21 [21]
I’m not sure what the answer is but I hope someone can help!! Maybe answer choice B?
8 0
2 years ago
Consider the reaction.
Alekssandra [29.7K]

Answer:The correct answer is option C.

Explanation:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

At STP, 1 mol of gas occupies 22.4 L of volume

So, 100.0 L volume of NH_3will be occupied by :

\frac{1}{22.4 L}\times 100.0 L=4.4642 moles

According to reaction 2 moles NH_3 are obtained from 1 mole of N_2.

Then,4.4642 moles of NH_3 will be obtained from :

\frac{1}{2}\times 4.4642 that is 2.2321 moles of N_2

Mass of N_2 gas:

Moles of N_2 gas  Molar mass of N_2 gas:

2.2321 mol\times 28 g/mol=62.4988\approx 62.50 g

Hence, the correct answer is option C.

4 0
3 years ago
Read 2 more answers
A toxicologist studying mustard gas, S(CH2CH2Cl)2, a blistering agent, prepares a mixture of 0.675 M SCl2and 0.973 M C2H4 and al
Musya8 [376]

Answer:

The value of K_p is 0.02495.

Explanation:

Initial concentration of SCL_2 gas = 0.675 M

Initial concentration of C_2H_4 gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)

initially

0.675 M            0.973 M        0

At equilibrium ;

(0.675-0.35) M            (0.973-2 × 0.35) M        0.35 M

The equilibrium constant is given as :

K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}

=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}

K_c=14.45

The relation between K_p and K_c are :

K_p=K_c\times (RT)^{\Delta n}

where,

K_p = equilibrium constant at constant pressure = ?

K_c = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

\Delta n = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}

K_p=6.2\times 10^{4}

K_p=0.02495

The value of K_p is 0.02495.

7 0
2 years ago
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