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natulia [17]
3 years ago
6

Why are water storage tanks usually built on towers or hilltops??

Physics
1 answer:
Komok [63]3 years ago
8 0

Because when you open the faucet, you want the water to
rush out with pressure, not just dribble or ooze out.  The
water has to be supplied to the user with pressure.  Either
you supply it from a height, or else you'll need to use pumps
to make the pressure.

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What is the definition for the word energy?​
Lena [83]
Kinetic, thermal and electrical. There is more then one form of energy
4 0
3 years ago
The slope of the line on a speed-time graph tells the speed.
iren2701 [21]

From the choices provided, the better answer is ' T ' .

8 0
3 years ago
How long( in hours, will it take for 500 000 C of charge to flow through a diode if it requires
Alina [70]

Answer:

277.78 hours

Explanation:

The formula for calculating the amount of charge is expressed as;

Q = It

I is the current

t is the time

Given

I =0.05A

Q = 50,000C

Required

Time t

Recall that: Q = It

t = Q/I

t = 50,000/0.05

t = 1,000,000secs

Convert to hours

1,000,000secs  = 1,000,000/3600

1,000,000secs = 277.78 hours

Hence it will take 277.78 hours for the charge to flow through the diode

6 0
3 years ago
The density of table sugar is 1.59 g/cm3. What is the volume of 7.85 g of sugar?
Likurg_2 [28]
\frac{7.85g }{1.59 \frac{g}{ cm^{3} } } = 4.937 cm^{3}
4 0
4 years ago
Consider one such cell where the magnitude of the potential difference is 65 mV, and the inner surface of the membrane is at a h
Gelneren [198K]

Answer: W = 1.04.10^{-20} J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

W=q.\Delta V

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = 1.6.10^{-19} C

To determine work in joules, potential has to be in Volts, so:

\Delta V=65.10^{-3}V

Then, work is

W=1.6.10^{-19}.65.10^{-3}

W=1.04.10^{-20}

To move a potassium ion from the exterior to the interior of the cell, it is required W=1.04.10^{-20}J of energy.

8 0
3 years ago
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