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worty [1.4K]
3 years ago
12

How is helium which is produced by the conversion of hydrogen into energy related to the solar core

Chemistry
2 answers:
qaws [65]3 years ago
3 0
The sun's core is where Hydrogen atoms produce energy as they convert to molecules of Helium. Helium that is produced by the conversion of hydrogen into energy is related to the solar core in the sense that the conversion process produces energy captured in the core. I hope this helps you. 
ZanzabumX [31]3 years ago
3 0

Answer : The phenomenon called as Nuclear Fusion is observed in the sun's core or solar core, where 4 atoms of Hydrogen molecule combines to give two atoms of Helium. It is due to fusing of two Hydrogen atoms to form one Helium molecule. In the core of sun this fusion process occurs, changing of mass of Hydrogen atom into Helium releases lot of energy in the form of heat and light.


The reaction that occurs inside the solar core is given below;


 4 H^{1}_{1} ----> He^{4}_{2}

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A solution containing 20.0 g of an unknown liquid and 110.0 g water has a freezing point of .32 °C. Given Kf 1.86°C/m for water,
hjlf

Answer:

A. 256

Explanation:

In a solution where a liquid is the sovent, we'll use the van't Hoff factor, which is the ratio between the number of moles of particles produced in solution and the number of moles of solute dissolved, will be equal to 1.

ΔTemp.f = i * Kf * b

where,

ΔTemp.f = the freezing-point depression;

i = the van't Hoff factor

Kf = the cryoscopic constant of the solvent;

b = the molality of the solution.

So the freezing-point depression by definition is the difference between the the freezing point of the pure solvent and the freesing point of the solution.

Mathematically,

ΔTemp.f = Temp.f° - Temp.f

where,

Temp.f° = the freezing point of the pure solvent.

Temp.f = the freezin point of the solution.

Freezing point of pure water = 0°C

ΔTemp.f = 0 - (-1.32)

= 1.32°C

i = 1,

Kf = 1.86 °Ckg/mol

Solving for the molality, b = ΔTemp.f/( i * Kf)

= 1.32/(1*1.86)

= 0.71 mol/kg

Converting from mol/kg to mol/g,

0.71 mol/kg * 1kg/1000g

= 0.00071 mol/g.

Mass of solvent = 110g

Number of moles = mass * molality

= 0.00071 * 110

= 0.078 mol.

To calculate molar mass,

Molar mass (g/mol) = mass/number of moles

Mass of solute (liquid) = 20g

Molar mass = 20/0.078

= 256.2 g/mol

4 0
3 years ago
✝️WARNING JESUS✝️IS COMING✝️COPY AND PASTE THIS✝️DO MORE CAN SEE THIS✝️SHARE THE GOSPEL✝️JESUS IS KING
Ierofanga [76]
Amen god is great, I’m glad there is nice Christians like you:)
7 0
3 years ago
Why we are advice to use fossil fuel only when absolutely necessary?​
trasher [3.6K]

Answer:

Hello there! For some reason Brainly detects my answers as containing swear words in them when they do not. Hence, the answer is going to be in the comments. Enjoy!

Explanation:

Hope this helped!

4 0
3 years ago
Calculate the volume in liters of a 0.00183g / L mercury(1) chloride solution that contains 125 mg of (Hg 2 Cl 2 ) .
tatiyna

Answer: 68.3L

Explanation:

Density = Mass / Volume

Density =  0.00183 g/L

Mass = 125 mg =  0.125g

Volume =     Mass / Density  =  68.3L

6 0
3 years ago
CaCO3 → CaO + CO2 Calculate the theoretical yield of Calcium Oxide if 24.8 grams of Calcium Carbonate decomposes. Calculate the
RideAnS [48]

Answer:

Theoretical yield: 13.9 g

Percent yield: 94 %

Explanation:

The reaction is:

CaCO₃ → CaO + CO₂

We see that the reaction is correctly balanced.

1 mol of calcium carbonate can decompose to 1 mol of calcium oxide and 1 mol of carbon dioxide.

We convert the mass to moles: 24.8 g . 1mol / 100.08g = 0.248 moles

As ratio is 1:1, 0.248 moles of salt can decompose to 1 mol of oxide.

We convert the moles to mass: 0.248 mol . 56.08g /1mol = 13.9 g

That's the theoretical yield.

To determine the percent yield we think:

(Determined yield / Theoretical yield) . 100 → (13.1 / 13.9) . 100 = 94 %

5 0
3 years ago
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