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IgorLugansk [536]
3 years ago
10

A 3.53g sample of (NH4NO3) was added to 80.0mlof water in a constant pressure calorimeter of negligible heat capacity. As a resu

lt the temperature of the water decreased from 21.6C to 18.1C Calculate the heat of solution of NH4NO3. Help me ....
Chemistry
1 answer:
raketka [301]3 years ago
7 0
Mass of water = 80 x 18
= 1440 grams

Specific heat of water = 4.186 J/gK

Heat absorbed from water = mCpΔT
= 1440 x 4.186 x (21.6 - 18.1)
= 21.1 kJ

Moles of NH₄NO₃ = 3.53 / (14 + 4 + 14 + 16 x 3)
= 0.044 mol

Heat of solution = 21.1/0.044 kJ/mol
= 480 kJ/mol
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Please help! Thanks
trapecia [35]

Th actual yield of the reaction is 24.86 g

We'll begin by calculating the theoretical yield of the reaction.

2Na + Cl₂ → 2NaCl

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced = 2 × 58.5 = 117 g

From the balanced equation above,

46 g of Na reacted to produce 117 g of NaCl.

Therefore,

11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.

Thus, the theoretical yield of NaCl is 29.25 g.

Finally, we shall determine the actual yield of NaCl.

  • Percentage yield = 85%
  • Theoretical yield = 29.25 g
  • Actual yield =?

Actual yield = Percent yield × Theoretical yield

Actual yield = 85% × 29.25

Actual yield = 0.85 × 29.25 g

Actual yield = 24.86 g

Learn more about stoichiometry: brainly.com/question/25899385

7 0
2 years ago
What is the value of quantum numbers (n, l, ml, ms) of 2p^3?​
eduard

Answer:

Explanation:

First digit of the 2p^3  gives you value of n,  in this case its = 2, So, n= 2

Second alphabet gives you the value of l,

l=0 =s

l=1 =p

l=3=d

l=4=f

since  "p" is the alphabet  in 2p^3, so in your case lt shoudlbe = 1 right?

ml= -l to +l , that is -1, 0, +1

Ms= +1/2  or -1/2 alaways remains same foe evrything.

6 0
3 years ago
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