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ZanzabumX [31]
3 years ago
12

How are the movements of the Moon in the sky and Earth's rotation about its own axis related? A) The Moon appears to move from E

ast to West due to Earth's East-to-West rotation. B) The Moon appears to move from East to West due to Earth's West-to-East rotation. C) The Moon actually moves from East to West while Earth rotates from West to East. D) The Moon and Earth both move from East to West, but Earth rotates at a lower speed.
Physics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

Earth rotates from West to East about its own axis. As a result of this, the Moon changes its position during the night. So the Moon appears to move from East to West in the sky due Earth's West-to-East rotation.

Explanation:

JulsSmile [24]3 years ago
7 0

The moon orbits quite fast: it moves about 0.5 degrees per hour in the sky. In 24 hours it moves 13 degrees. The moon's observed motion eastward results from its physical motion of the moon along its orbit around the Earth. so I think its A .

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Varvara68 [4.7K]

Answer:

The answer is "Option C".

Explanation:

Computation modeling is used as the software for math, physics, or software engineering in the simulation and study of complicated processes. The software framework incorporates many parameters, that characterize the model under study. It is a computer program, in which the mathematical formula is generated by computers and research complex systems.

4 0
2 years ago
A net force of 125 n is applied to a certain object. as a result, the object accelerates with an acceleration of 24.0 m/s2. the
pantera1 [17]
Newton's second law states that Fnet = ma, where Fnet is the net force applied, m is the mass of the object, and a is the object's acceleration. You have the values for Fnet and a, so you simply use this equation to solve for m, mass.
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3 years ago
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Compare mass and weight
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Answer:

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3 years ago
What is the purpose of a circuit breaker?
sashaice [31]
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8 0
3 years ago
A motor has an armature resistance of 3.75 Ω . Part A If it draws 9.10 A when running at full speed and connected to a 120-V lin
bulgar [2K]

Back emf is 85.9 V.

<u>Explanation:</u>

Given-

Resistance, R = 3.75Ω

Current, I = 9.1 A

Supply Voltage, V = 120 V

Back emf = ?

Assumption - There is no effects of inductance.

A motor will have a back emf that opposes the supply voltage, as the motor speeds up the back emf increases and has the effect that the difference between the supply voltage and the back emf is what causes the current to flow through the armature resistance.

So if 9.1 A flows through the resistance of 3.75Ω then by Ohms law,

The voltage across the resistance would be

v = I x R

  = 9.1 x 3.75

  = 34.125 volts

We know,

supply voltage = back emf + voltage across the resistance

By plugging in the values,

120 V = back emf + 34.125 V

Back emf = 120 - 34.125

                = 85.9 Volts

Therefore, back emf is 85.9 V.

4 0
3 years ago
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