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Ede4ka [16]
3 years ago
15

How are the direction of the net force on an object and the direction of the object’s acceleration related?

Physics
1 answer:
Oksanka [162]3 years ago
8 0

They're the same direction.

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Will give brainliest! 50 points!!!
tatiyna

Answer:

C

Im not totally sure but that's what my science teacher taught me sorry if is wrong

6 0
3 years ago
True or False an overtone occurs when two or more sound waves are produced at the same time.
Setler79 [48]

Answer:

True, overtone occurs when two or more sounds are produced at the same time.

5 0
3 years ago
Read 2 more answers
A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the
Anni [7]

Answer:

I=38.181\ A is the current through the body of the man.

E=34.5\ J energy dissipated.

Explanation:

Given:

  • time for which the current lasted, t=43\times 10^{-6}\ s
  • potential difference between the feet, V=21000\ V
  • resistance between the feet, R=550\ \Omega

<u>Now, from the Ohm's law we have:</u>

I=\frac{V}{R}

I=\frac{21000}{550}

I=38.181\ A is the current through the body of the man.

<u>Energy dissipated in the body:</u>

E=I^2.R.t

E=38.181^2\times 550\times 43\times 10^{-6}

E=34.5\ J

5 0
3 years ago
Influenced by the gravitational pull of a distant star, the velocity of an asteroid changes from from +19.3 km/s to −18.8 km/s o
muminat

As per above given data

initial velocity = 19.3 km/s

final velocity = - 18.8 km/s

now in order to find the change in velocity

\Delta v = v_f - v_i

\Delta v = -18.8 - 19.3

\Delta v = -38.1 km/s

\Delta v = -3.81 * 10^4 m/s

Part b)

Now we need to find acceleration

acceleration is given by formula

a = \frac{\Delta v}{\Delta t}

given that

\Delta v =- 3.81 * 10^4 m/s

\Delta t = 2.07 years = 6.53 * 10^7 s

now the acceleration is given as

a = \frac{-3.81 * 10^4}{6.53 * 10^7}

a = - 5.84 * 10^{-4}m/s^2

so above is the acceleration

4 0
3 years ago
Capacitors C1 = 6.45 µF and C2 = 2.50 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon
denpristay [2]

Answer:

For C1, Q =  1.6125×10⁻³ C

For C2, Q =  6.25×10⁻⁴ C

Explanation:

Note: Since the capacitors are connected in parallel, The voltage across each of them is equal.

From the question,

Q = CV........................ Equation 1

Where Q = Charge on the capacitor, V = Voltage across the capacitor, C = Capacitance of the capacitor.

For the first capacitor,

Q = C1V............. Equation 2

Where C1 = 6.45 μF= 6.45×10⁻⁶ F, V = 250 V

Substitute into equation 2

Q = (6.45×10⁻⁶ )(250)

Q = 1.6125×10⁻³ C.

For the the second capacitor,

Q = C2V............. Equation 3

Given: C2 = 2.50 μF = 2.5×10⁻⁶ F, V = 250 V

Q = (2.5×10⁻⁶ )(250)

Q = 6.25×10⁻⁴ C

4 0
3 years ago
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