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Ostrovityanka [42]
3 years ago
11

Which of the following determines whether light shining on a metal surface will eject electrons from that surface?

Physics
1 answer:
PtichkaEL [24]3 years ago
8 0
From that list, only the frequency makes the difference.

Einstein won his only Nobel Prize for his explanation of this effect.
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Suppose that a sound source is emitting waves uniformly in all directions. If you move to a point twice as far away from the sou
Helen [10]

Answer:

<em>d. unchanged.</em>

Explanation:

The frequency of a wave is dependent on the speed of the wave and the wavelength of the wave. The frequency is characteristic for a wave, and does not change with distance. This is unlike the amplitude which determines the intensity, which decreases with distance.

In a wave, the velocity of propagation of a wave is the product of its wavelength and its frequency. The speed of sound does not change with distance, except when entering from one medium to another, and we can see from

v = fλ

that the frequency is tied to the wave, and does not change throughout the waveform.

where v is the speed of the sound wave

f is the frequency

λ is the wavelength of the sound wave.

4 0
2 years ago
if a ball is rolling at a velocity of 1.5 m/sec and has the momentum of 10.0 kg m/sec, what is the mass of the ball?
PolarNik [594]
Okay. There is a simple formula to go with this where:

p = mv

P: Momentum.
M: Mass.
V: Velocity

Sub the numbers in and solve for M.

10.0 = m(1.5)
10.0/1.5 = m
6.67 kg = m

Therefore the mass of the ball is 6.67kg.
6 0
2 years ago
Consider a semi-spherical bowl machined out of wood (A drawing of a semi-spherical bowl can be found in UNIT- 4 Introduction, so
Mrrafil [7]

Answer:

The total surface are of the bowl is given by: 0.0532*pi m² (approximately 0.166533 m²)

Explanation:

The total surface area of the semi-spherical bowl can be decomposed in three different sections: 1) an outer semi-sphere of radius 12 cm, 2) an inner semi-sphere of radius 10 cm, and 3) the edge, which is a 2-dimensional ring with internal radius of 10 cm and external radius of 12 cm. We will compute the areas independently and then sum them all.

a) Outer semi-sphere:

A1 = 2*pi*r² = 2*pi*(12 cm)² = 288*pi cm² = 904.78 cm²

b) Inner semi-sphere:

A2 = 2*pi*(10 cm)² = 200*pi cm² = 628.32 cm²

c) Edge (Ring):

A3 = pi*(r1² - r2²) = pi*((12 cm)²-(10 cm)²) = pi*(144-100) cm² = 44*pi cm² = 138.23 cm²

Therefore, the total surface area of the bowl is given by:

A = A1 + A2 + A3 = 288*pi cm² + 200*pi cm² + 44*pi cm² = 532*pi cm² (approximately 1665.33 cm²)

Changing units to m², as required in the problem, we get:

A = 532*pi cm² * (1 m² / 10, 000 cm²) = 0.0532*pi m² (approximately 0.166533 m²)

5 0
3 years ago
A 210 Ohm resistor uses 9.28 W of
IgorLugansk [536]
  • Resistance=R=210Ohm
  • Power=9.28W=P

Current=I

\boxed{\sf P=I^2R}

\\ \sf\longmapsto I^2=\dfrac{P}{R}

\\ \sf\longmapsto I^2=\dfrac{9.28}{210}

\\ \sf\longmapsto I^2\approx0.04

\\ \sf\longmapsto I\approx\sqrt{0.04}

\\ \sf\longmapsto I\approx\sqrt{\dfrac{4}{100}}

\\ \sf\longmapsto I\approx\dfrac{\sqrt{4}}{\sqrt{100}}

\\ \sf\longmapsto I\approx\dfrac{2}{10}

\\ \sf\longmapsto I\approx0.2A

4 0
2 years ago
Why is it important to practice a presentation?
-Dominant- [34]
Your answer should be D
let me know if I got it wrong
Hope this helped!
6 0
3 years ago
Read 2 more answers
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