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AysviL [449]
3 years ago
11

The distance between the crests of waves

Physics
2 answers:
stepladder [879]3 years ago
8 0
It depends, You have to have the length and the width of the crest wave.
Ivanshal [37]3 years ago
7 0
You need the length and width of the crest waves. -_-
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Benjamin Franklin, George Washington, and the brothers

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The gravitational force between two objects<span> is </span>proportional<span> to their </span>masses,<span> and inversely </span>proportional<span> to the square of the distance </span>between<span> their centers.</span>
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A tank is 3 m long 1 m wide and 0.5 m deep is filled with oil which weighs 12000 N
Finger [1]
Area of the bottom = L x W = 3 x 1 = 3 square meters. Pressure = force/area = 12000/3 = 4000 N/square meter = 4 kPa. Since we know the weight of the oil, we don't need to know the depth.
5 0
3 years ago
You are in a boat that is 1400 kg. The current is 1500N and is pushing you back. If you have an acceleration of 3 m/s^2 what is
aleksandrvk [35]

Answer: The force of the engines is 5700N

Explanation:

By the second Newton's law, we have that:

F = m*a

Force equals mass times acceleration.

In this case, we have:

m = 1400kg

a = 3 m/s^2

And the force will be equal to the force of the engines, f, plus the force of  the current, -1500 N (because this is pushing you back, so it is in the opposite direction than f), then we have:

F = f - 1500N

Then we have the equation:

f - 1500N = 1400kg*3m/s^2 = 4200N

f - 1500N = 4200N

f = 4200N + 1500N = 5700N

The force of the engines is 5700N

5 0
3 years ago
find the time taken, if the speed of a train increased from 72 km/hr to 90 km/hr for 234 km. leave your answer in seconds
Airida [17]

Answer:

Time taken = 10400 s

Explanation:

Given:

Initial speed of the train, u=72\textrm{ km/h}=72\times \frac{5}{18}=20\textrm{ m/s}

Final speed of the train, v=90\textrm{ km/h}=90\times \frac{5}{18}=25\textrm{ m/s}

Displacement of the train, S=234\textrm{ km}=234\times 1000=234000\textrm{ m}

Using Newton's equation of motion,

v - u = at\\a=\frac{v-u}{t}

Now, using Newton's equation of motion for displacement,

v^{2}-u^{2}=2aS

Now, plug in the value of a=\frac{v-u}{t} in the above equation. This gives,

v^{2}-u^{2}=2\times \frac{v-u}{t}\times S\\(v+u)(v-u)=\frac{2(v-u)S}{t}\\t=\frac{2(v-u)S}{(v+u)(v-u)}\\t=\frac{2S}{v+u}

Now, plug in 234000 m for S, 25 m/s for v and 20 m/s for u. Solve for t.

t=\frac{2S}{v+u}\\t=\frac{2\times 234000}{25+20}\\t=\frac{468000}{45}=10400\textrm{ s}

Therefore, the time taken by the train is 10400 s.

3 0
4 years ago
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