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Andrews [41]
2 years ago
13

Remember KE=M*V2/2…
 A model airplane moves twice as fast as another identical model airplane. Compared with the kinetic energy

of the slower airplane, the kinetic energy of the faster airplane is​
Physics
1 answer:
pishuonlain [190]2 years ago
4 0

Answer: 4 times as much

Explanation:

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A moving truck has more __ energy than a parked truck
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For pea plants, T represents a dominant allele for tall pea plants and t is the recessive allele for short pea plants. If two pl
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75%(TT,Tt,tt) Hope that helps

4 0
2 years ago
You are driving 12 meters per second. What is your speed in miles per hour? (1.6km=1 mike) EXPLAIN
Blizzard [7]

1.6km = 1 mike? Wow that guy is tall.

I think you meant 1.6 km = 1 mile? Okay then if we're going 12 meters per second how much would you travel in one hour? First we need to figure out how many seconds are in an hour.  There are 60 seconds in a minute and 60 minutes in an hour so:

60×60=3600 seconds in an hour

Now we will multiply that by 12 meters per second and we get:

12\frac{m}{s} \times 3600 s=43200m

And 43200 meters is 43.2 km (1000 meters in 1 kilometer) meaning 43.2 kilometers an hour.  Since there are 1.6 km in one mile we must divide 43.2km to 1.6.

\frac{43.2}{1.6}=27mph

And so your speed is 27 miles per hour.

8 0
4 years ago
A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500-kg particle res
garri49 [273]

Answer:

ω = 22.36 Hz

f = 3.56 Hz

T = 0.28 s.      

Explanation:

a) The angular frequency (ω), can be calculated using the following equation:

\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{F}{x*m}}  

<u>Where:</u>

<em>k: is the spring constant = F/x</em>

<em>m: is the mass of the particle = 0.500 kg</em>

<em>F: is the force applied = 7.50 N       </em>

<em>x: is the displacement = 3.00 cm = 0.03 m </em>            

\omega = \sqrt{\frac{7.50 N}{0.03 m*0.500 kg}} = 22.36 s^{-1} = 22.36 Hz    

Therefore, the angular frequency of the motion is 22.36 Hz.

b) To find the frequency (f) we can use the next equation:

f = \frac{\omega}{2 \pi} = \frac{22.36 Hz}{2 \pi} = 3.56 Hz

Hence, the frequency of the motion is 3.56 Hz.

c) The period (T) is equal to:

T = \frac{1}{f} = \frac{1}{3.56 Hz} = 0.28 s

Therefore, the period of the motion is 0.28 s.

I hope it helps you!

4 0
4 years ago
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