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2 years ago

11

Which type of force could be used to pull up on a metal paper clip without

1 answer:

solmaris [256]2 years ago

5 0

Answer:

Magnetic force

Explanation:

Because a paper clip is type of a metal and magnets and paper clip get pulled to each other.

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A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed

Katarina [22]

Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object $m_1=52 kg$

distance of $m_1$ from the axle $r_1=14 cm$

mass of rock $m_2=123 gm$

Length of rod $=4.1 m$

distance of $m_2$ from axle $r_2=4.1-0.14=3.96 m$

Net torque acting is

$T_{net}=m_1gr_1-m_2gr_2$

$T_{net}=52\times 0.14\times g-0.123\times 3.96\times g$

$T_{net}=6.793\times 9.8$

$T_{net}=66.57 N-m$

Work done by $T_{net}$ is converted to rock kinetic Energy

thus

$T_{net}\times \theta =\frac{mv^2}{2}$

Where $\theta =angle\ turned =\frac{\pi }{2}$

$v= velocity\ at\ launch$

$66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}$

$v^2=66.57\times \pi$

$v=\sqrt{1700.511}$

$v=41.23 m/s$

3 0

3 years ago

A net force of 24 N is acting on a 4.0-kg object. Find the acceleration in m/s2.

Inessa [10]

Hi there!

We can use Newton's Second Law:
$\Sigma F = ma$

ΣF = Net force (N)
m = mass (kg)
a = acceleration (m/s²)

We can rearrange the equation to solve for the acceleration.

$a = \frac{\Sigma F}{m}\\\\a = \frac{24}{4} = \boxed{6 \frac{m}{s^2}}$

6 0

1 year ago

A longitudinal wave is shown.<br> Which label identifies a rarefaction?

aev [14]

Answer:

B.

Explanation:

9 0

2 years ago

The equilibrium reaction for calcium sulfate is shown here. What is the effect on the equilibrium reaction if calcium nitrate is

natta225 [31]

Answer:

a

Explanation:

8 0

2 years ago

Read 2 more answers

Mercury is a liquid metal having a density of 13.6 g/mL. What is the

sergij07 [2.7K]

Answer:

$\boxed {\boxed {\sf v \approx 33.088 \ mL}}$

Explanation:

The formula for density is:

$d= \frac{m}{v}$

where <em>m</em> is the mass and <em>v</em> is the volume.

The mass is 0.45 kilograms and the density is 13.6 grams per milliliter. The density is given in grams, so we must convert the mass.

There are 1000 grams in 1 kilogram or $\frac{1000 \ g} {1 \ kg}$ . We can multiply the mass by this ratio.

$0.45 \ kg * \frac{1000 \ g} {1 \ kg} = 0.45 * 1000 \ g = 450 \ g$

Now we have values for the mass and density:

$13.6 \ g/mL =\frac{450 \ g}{ v}$

Cross multiply.

$\frac {13.6 \ g/mL}{1} =\frac{450 \ g}{ v}$

$13.6 \ g/mL * v=450 \ g * 1 \\13.6 \ g/mL * v=450 \ g$

We are trying to find the volume, so we must isolate that variable.

13.6 and v are being multiplied. The inverse of multiplication is division. Divide both sides by 13.6

$\frac {13.6 \ g/mL*v } { 13.6 \ g/mL} = \frac{ 450 \ g} {13.6 \ g/mL}$

$v= \frac{ 450 \ g} {13.6 \ g/mL}$

The grams will cancel.

$v= 33.0882353 \ mL\\v \approx 33.088 \ mL$

The volume is about 33.088 milliliters.

3 0

2 years ago