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Answer:
The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%
Explanation:
Here we have
Propane gas with molecular formula C₃H₈, molar mass = 44.1 g/mol combining with O₂ as follows
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Therefore, 1 mole of C₃H₈ combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O
Mass of propane = 0.1240 kg = 124.0 g
Number of moles of propane = mass of propane/(molar mass of propane)
The number of moles of propane = 124/44.1 = 2.812 moles
The molar mass of CO₂ = 44.01 g/mol
Mass of CO₂ = 0.3110 kg = 311.0 g
Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)
The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles
Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂
Therefore;
The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess
Hence
The percentage yield = 83.77%.
Answer : The correct answer is 74.83 m/s .
The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :
Where KE = kinetic energy in J or m = mass in Kg v = speed in m/s²
Unit of KE is Joules (J) .
Givne : KE = 2100 J mass = 0.75 kg v = ?
Plugging value in KE formula =>
Dividing both side by 0.375 kg =>
<u>Answer:</u> The partial pressure of helium gas is 0.80 atm
<u>Explanation:</u>
Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.
To calculate the partial pressure of helium gas, we use the law given by Dalton, which is:
We are given:
Total pressure of the cylinder, = 1.00 atm
Vapor pressure of oxygen gas, = 0.20 atm
Putting values in above equation, we get:
Hence, the partial pressure of helium gas is 0.80 atm