Answer:
3.14 m/s
Explanation:
We are given that
Mass of object=1.1 Kg
Spring constant=160 N/m
a.We have to find the amount by which the spring is stretched from its unstrained length(it means x)
We know that F=kx ,
b.When an object is pulled straight down by an additional distance 0.26 m and released from rest.
x=0.26 m
We have to find the speed with which the object passes through its original position on the way up.
(Law of conservation of energy)
Substitute the values then we get
Hence, the speed of an object with which the object passes through its original position on the way up=3.14 m/s
Answer:
B. 4.29s
Explanation:
If the man appears to move 12.4m/s when the boat appears to move 11m/s, it means that the man moves 1.4m on the boat (12.4-11=1.4). So if the man moves 1.4m per second then it will take him 6/1.4=4.29s to move 6 m relative to the boat.
Hope this helped!
I would say because they have the same negative charge and they repel each other
Cathode Ray Tube i think?