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2 years ago

Need help I'll give you 30 points please.

Physics

1 answer:

Ksivusya [100]2 years ago

7 0

Cathode Ray Tube i think?

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A boy throws a stone straight upward with an initial

Dominik [7]

Answer:

14.8m

Explanation:

Given parameters:

Initial speed = 17m/s

Unknown:

Maximum height = ?

Solution:

At the maximum height, the final speed will be 0m/s;

We use of the kinematics equation to solve this problem.

V² = U² - 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

0² = 17² - (2 x 9.8 x h )

0 = 289 - (9.6h)

-289 = -19.6h

h = 14.8m

5 0

2 years ago

An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the

alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

$X=V_{o}*t + \frac{a*t^{2}}{2}$ Replacing the known values:

$1500=6t+0.9*t^{2}$ Solving for t we get 2 possible answers:

t1 = -44.3s and t2 = 67.7s Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

8 0

2 years ago

The propeller of a WW2 fighter plane is 2.35 m in diameter

Studentka2010 [4]

A) 1 rev = 2π rad. Using this ratio, you can find the rad/s: 1160 rev/min x 2π rad/rev x 1 min/60 s = 121.5 rad/s

b) You can find linear speed from angular speed using this equation (note the radius is half the diameter given in the question): v = ωr = 121.5 rad/s x 1.175 m = 142.8 m/s

c) You can find centripetal acceleration using this equation: a = v^2/r = (142.8 m/s)^2 / 1.175 m = 17 355 m/s^2

8 0

2 years ago

Read 2 more answers

The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth

ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids