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dezoksy [38]
4 years ago
15

Rge vertical structures that help support the weight of the structure overhead?

Physics
1 answer:
makkiz [27]4 years ago
4 0
They are known as columns
You might be interested in
What is the frequency of a wave that has a speed of 0.6 m/s and a wavelength of 0.020 meter?
UNO [17]
The formula for wave motion is speed of wave equals frequency times wavelength.v = f lambdarearrangingf = v/lambdaf = 0.6/0.02 = 60/2 = 30Hz, or cycles per second.
7 0
3 years ago
The velocity of the transverse waves produced by an earthquake is 5.08 km/s, while that of the longitudinal waves is 8.3312 km/s
ASHA 777 [7]

Answer:

727.67 km

Explanation:

Sine they have Same distance D

distance = speed * time

D = 5.08t

D = 8.3312(t+55.9)

so

5.08t = 8.3312(t+55.9) t in

3.2512t = 465.71

t = 143.2s

Subtitute t

D=5.08 t

= 5.08 × 143.2

= 727.67km

7 0
3 years ago
Robert dropped his new iPhone from his balcony. It hit the ground 3.5 seconds later. What was the height of his balcony?
Lorico [155]

its B. 60 meters

Explanation:

cause I looked up a calculator and solved it

8 0
3 years ago
Can someone pleaseeee answer this !!!!!!
LenaWriter [7]

Answer:

The person with locked legs will experience greater impact force.

Explanation:

Let the two persons be of nearly equal mass (say m)

The final velocity of an object (person) dropped from a height H (here 2 meters) is given by,

v=\sqrt{2gH}

(g = acceleration due to gravity)

which can be derived from Newton's equation of motion,

v^2=u^2+2aS

Now, the time taken (say t ) for the momentum ( mv ) to change to zero will be more in the case of the person who bends his legs on impact than who keeps his legs locked.

We know that,

Force=\frac{\Delta(mv)}{t}

Naturally, the person who bends his legs will experience lesser force since t is larger.

3 0
3 years ago
For a spring oscillating in simple harmonic motion, at what point will the velocity of
Crazy boy [7]

Answer:

equilibrium position.

Explanation:

In simple harmonic motion , velocity v(t) is given by,

v(t) = -ω A sin(ωt + φ)

where

ω = angular velocity of the corresponding circular motion

A = amplitude

t = time

φ = the initial angle of the corresponding circular motion when the motion begin.

v (t) get maximized when sin value is maximized , i.e. sin \alpha=1

The particle has maximum speed when it passes through the equilibrium position.

6 0
4 years ago
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