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3 years ago

9

Vascular resistance is the friction force that opposes blood flow in a blood vessel. what two factors are the most important in

generating friction between blood and the walls of a vessel?

1 answer:

makvit [3.9K]3 years ago

6 0

The two most important factors are Systematic Vascular Resistance as and Vascular Resistance.

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An electron and a proton have the same kinetic energy upon entering a region of constant magnetic field and their velocity vecto

kupik [55]

Answer: rp/re= me/mp= 544 * 10^-6.

Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.

Then the dynamic equation for the circular movement is given by:

Fcentripetal= m*ω^2.r

q*v*B=m*ω^2.r

we write this for each particle then we have the following:

q*v*B=me* ω^2*re

q*v*B=mp* ω^2*rp

rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6

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3 years ago

Increasing the number of loops in a electromagnet or solenoid will cause it to be stronger

Zielflug [23.3K]

True

The electromagnet will become stronger if we add more coils because there are more field lines in a loop then there is in a straight piece of wire. In a solenoid there are a lot of loops and they are concentrated in the middle, as more loops are added the field lines get larger, therefore making the electromagnet stronger.

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3 years ago

Humberto builds two circuits using identical components.

vlada-n [284]

Humberto should expect to see that all bulbs in circuit 1 will shine more dimly than the original bulbs, while all bulbs in circuit 2 will have the same brightness as the original bulbs.

B) All bulbs in circuit 1 will shine more dimly than the original bulbs, while all bulbs in circuit 2 will have the same brightness as the original bulbs.

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3 years ago

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A basketball player makes a jump shot. The 0.599 kg ball is released at a height of 2.18 m above the floor with a speed of 7.05

7nadin3 [17]

Answer:

$W_{drag} = 4.223\,J$

Explanation:

The situation can be described by the Principle of Energy Conservation and the Work-Energy Theorem:

$U_{g,A}+K_{A} = U_{g,B} + K_{B} + W_{drag}$

The work done on the ball due to drag is:

$W_{drag} = (U_{g,A}-U_{g,B})+(K_{A}-K_{B})$

$W_{drag} = m\cdot g\cdot (h_{A}-h_{B})+ \frac{1}{2}\cdot m \cdot (v_{A}^{2}-v_{B}^{2})$

$W_{drag} = (0.599\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2.18\,m-3.10\,m)+\frac{1}{2}\cdot (0.599\,kg)\cdot [(7.05\,\frac{m}{s} )^{2}-(4.19\,\frac{m}{s} )^{2}]$

$W_{drag} = 4.223\,J$

7 0

3 years ago

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A circular conical reservoir has depth 20 feet and radius of the top 10 feet. water is leaking out so that the surface is fallin

levacccp [35]

As per given condition we know that vertex angle of the cone is given as

$tan\theta = \frac{R}{H}$

so here we can say that vertex angle will remain constant

so here

$\frac{r}{y} = \frac{R}{H}$

$\frac{r}{8} = \frac{10}{20}$

$r = 4 feet$

now for the volume we can say

$V = \frac{1}{3}\pi r^2 y$

also we can say

$r = \frac{y}{2}$

so here we will have

$V = \frac{1}{3}\pi (\frac{y}{2})^2y = \frac{1}{12}\pi y^3$

now for volume flow rate

$Q = \frac{dV}{dt} = \frac{3}{12}\pi y^2\frac{dy}{dt}$

$Q = \frac{1}{4}\pi y^2 v_y$

now plug in all data

$Q = \frac{1}{4} \pi (8)^2 (12) ft^3/h$

$Q = 603.2 ft^3/h$

4 0

3 years ago