Does the temperature of the water change the fluid pressure in the water?
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Answer:
<em>The radius of the balloon is R= 0.974 m</em>
Explanation:
Atmospheric density on the surface of mars ρ = 0.0154 kg/m³
Mass density of balloon σ 5 gm/m² = 0.005 kg/m²
Total mass of balloon M = density of balloon* surface area
The balloon is considered as sphere
Surface area of sphere is given by 4π R²
Mass of balloon is M =σ *4πR²
M= (0.005 kg/m²)*(4π R²)
Volume of balloon is given by πR³
Density of atmosphere of mass is given by
ρ = Mass of balloon/volume of balloon
=(0.005 kg/m²)*(4π R²)/ πR³
Re arranging R
R =
R = 0.974 m
<em>The radius of the balloon is R= 0.974 m</em>
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