Answer: option B. there are 35 mg of lead in 1.0 L of this solution
Explanation:
1ppm = 1mg/L
Therefore 35ppm = 35mg/L
So, the solution contains 35mg of lead in 1L of the solution
Answer:
a
Explanation:
it would be the most reasonable
Cr2(SO4)3(aq) + 3(NH4)2CO3(aq) → 3(NH4)2SO4(aq) + Cr2(CO3)3(s)
<span>Ionic: 2Cr+3 + 3SO4^-2 + 6NH4+ + 3CO3^-2 ----> 6NH4+ + 3SO4^-2 + Cr2(CO3)3 (spectator ions are NH4+, SO4^-2) </span>
<span>Net Ionic: 2Cr^+3(aq) + 3CO3^-2(aq) -------> Cr2(CO3)3(s) </span>
Answer:
A will float on top of B.
Explanation:
B is more dense. example A is oil and B is water.
Answer:
1x10⁻¹²
Explanation:
- Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq)
At equilibrium:
The equilibrium constant for the the reaction can be written as:
[Cu⁺] is squared because it has a stoichiometric coefficient of 2 in the reaction. <em>Cu₂S has no effect on the constant because it is a solid</em>.
Now we can <u>calculate the equilibrium constant</u>:
- Keq = (1.0x10⁻⁵)² * 1.0x10⁻² = 1x10⁻¹²