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3 years ago

What is the magnification of a virtual image if the image is 10.0 cm from a lens and the object is 30 cm from the lens

Physics

2 answers:

7nadin3 [17]3 years ago

5 0

Answer:

The magnification of a virtual image is -0.33

Explanation:

We can calculate the magnification as the ratio of height of the image to the height of the object. It can be also stated as the ratio of size of the image obtained to the original size of the object. Also this ratio can be equated to the ratio of image distance to object distance. So magnification can be termed as ratio of image distance to object distance. As in the present case, the image distance or the distance of the formation of image from the lens is 10 cm and the distance of object from the lens or the object distance is 30 cm. Then, $Magnification =-\frac{Image distance}{Object distance}=-\frac{10}{30}=-0.33$ .

So, the image will be diminished to 0.33 times the original size as the magnification of the virtual image is obtained as -0.33.

babymother [125]3 years ago

4 0

Answer:

The answer is 0.33

Explanation:

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Answer:

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Explanation:

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Answer:

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<h3>What do you mean by sound?</h3>

In terms of physics, the sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the reception of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between roughly 20 Hz and 20 kHz, or the audio frequency range, can cause a human to have an auditory sensation. These are sound waves with wavelengths ranging from 17 meters (56 ft) to 1.7 millimeters in the air at atmospheric pressure (0.67 in). Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges.

To learn more about sound, Visit:

brainly.com/question/9349349

#SPJ4

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