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aleksandr82 [10.1K]
4 years ago
15

Alonzo sprints for 500 meters along a straight track during a race. After crossing the finish line, he to walks back along the t

rack for 50 meters to cool down. What is Alonzo's displacement?
Physics
2 answers:
ehidna [41]4 years ago
8 0
450 meters is the displacement
Sveta_85 [38]4 years ago
3 0

So the answer should be 450 meters hope this helped :)

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What is the net charge (overall or sum of charges) of the nucleus and what number is it equal to?
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Because the nucleus is made up of positively charged protons and neutrally charged neutrons, and no negatively charged particles, the charge of the nucleus will always be equal to the sum of the charges of its protons. A simpler way to say it is because each proton has a +1 charge, the charge of the nucleus will be the same as the number of protons in it.
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3 years ago
What is the half-life of an isotope that decays to 25% of its original activity in 70.8 hours?
loris [4]
Are there any options?
8 0
3 years ago
A kangaroo jumps straight up to a vertical height of 1.45 m. How long was it in the air before returning to Earth?
dexar [7]

Answer:

1.08 s

Explanation:

From the question given above, the following data were obtained:

Height (h) reached = 1.45 m

Time of flight (T) =?

Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:

Height (h) = 1.45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

1.45 = ½ × 9.8 × t²

1.45 = 4.9 × t²

Divide both side by 4.9

t² = 1.45/4.9

Take the square root of both side

t = √(1.45/4.9)

t = 0.54 s

Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).

Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:

Time (t) taken to reach the height = 0.54 s

Time of flight (T) =?

T = 2t

T = 2 × 0.54

T = 1.08 s

Therefore, it will take the kangaroo 1.08 s to return to the earth.

3 0
3 years ago
HELP
dem82 [27]

Answer:

Explanation:

28 / 70 = 0.3857142...  = 0.39 hr

280 / 100 = 2.8 hrs.

(100 - 0) / 10 = 10 m/s²

(60 - 20) / 4 = 10 m/s²

3 0
3 years ago
1. The term that describes where the supply curve intersects the demand curve is known as
nadezda [96]
Equilibrium is the answer
6 0
3 years ago
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