Answer: The question is incomplete or some details are missing. Here is the complete question ; (a) The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of −5.55 m/s2 for 4.05 s, making straight skid marks 63.0 m long, all the way to the tree. With what speed (in m/s) does the car then strike the tree? m/s
(b) What If? If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2
a ) With what speed (in m/s) does the car then strike the tree? m/s = 4.3125m/s
b) then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2 = -5.696m/s2
Explanation:
The detailed steps and calculation is as shown in the attached file.
What does "a 4-inch candle" mean ?
Is that the length of the candle or its diameter ?
The life of a candle depends on its length, its diameter, the
thickness and starting-length of its wick, the exact substance
of which it's composed ... the type of wax ... and the motions
of the air around it.
I'll always remember the candle shop I visited ... I don't remember
what I was doing in a candle shop, but I was there. There was a
little wax turkey up on a glass shelf, with a tiny tiny flame in the
middle of its back, so tiny that you could easily miss noticing it.
The little sign standing next to the little turkey on the shelf explained
that this was a Thanksgiving candle ... it was lit last Thanksgiving,
and would continue burning until NEXT Thanksgiving, roughly a year later !
Answer:
271.095 m
Explanation:
✓ Let speed of sound in air that was given as (343 m/s) be represented as (Vi)
✓( speed of sound in concrete that was given as (3000 m/s ) be debited as (Vc)
✓ Let the distance travelled by the sound = s
✓duration of Time that exist between heard of sounds = 0.70s
But we know that
Time = (Distance / Speed)
✓Time it takes the sound to travel through air= s/vi = s/343
✓Time it takes the sound to travel through concrete= s/vc = s/3000
✓ (s/343) - (s/3000) = 0.70
Finding LCM and simplify
[(3000s - 343s)]/1029000 = 0.70
2657s /1029000 = 0.70
Making " s" subject of the formula
s= (1029000 × 0.70)/2657
s=720300/ 2657
s= 271.095 m
Hence, The impact took place at a distance of 271.095 m away from the person.
7(a) transpiration is faster in warmer dry air
(b)(I)xylem
(ii) 1. They are stacked end-to-end
2. Consists of dead cells
