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Svetradugi [14.3K]
3 years ago
9

An ideally efficient steamboat engine operates on 520 K steam in 270 K weather. How much work can it obtain when 500 J of heat l

eaves the steam?
Physics
1 answer:
Vesna [10]3 years ago
3 0

Answer:

240 J

Explanation:

Efficiency is given by, e=\frac {T_s-T_w}{T_s} where T is temperature and subscripts s and w to represent steam and normal weather respectively. Substituting temperature of steam and normal weather with with the given figures then efficiency will be e=\frac {520-270}{520}\approx 0.48

Also, work done by engine is given by,

W=Qe =0.48*500=240 J

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