We are given a box that slides up a ramp. To determine the force of friction we will use the following relationship:

Where.

To determine the Normal force we will add the forces in the direction perpendicular to the ramp, we will call this direction the y-direction as shown in the following diagram:
In the diagram we have:

Adding the forces in the y-direction we get:

Since there is no movement in the y-direction the sum of forces must be equal to zero:

Now we solve for the normal force:

To determine the y-component of the weight we will use the trigonometric function cosine:

Now we multiply both sides by "mg":

Now we substitute this value in the expression for the normal force:

Now we substitute this in the expression for the friction force:

Now we substitute the given values:

Solving the operations:

Therefore, the force of friction is 15.01 Newtons.
The shot putter should get out of the way before the ball returns to the launch position.
Assume that the launch height is the reference height of zero.
u = 11.0 m/s, upward launch velocity.
g = 9.8 m/s², acceleration due to gravity.
The time when the ball is at the reference position (of zero) is given by
ut - (1/2)gt² = 0
11t - 0.5*9.8t² = 0
t(11 - 4.9t) = 0
t = 0 or t = 4.9/11 = 0.45 s
t = 0 corresponds to when the ball is launched.
t = 0.45 corresponds to when the ball returns to the launch position.
Answer: 0.45 s
Answer:
this situation would not be physically possible