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3 years ago

The ability of sculptural material to resist forces of pressure, like gravity, is called its __________.

Physics

1 answer:

Vitek1552 [10]3 years ago

3 0

I think the answer would be tensile, I’m sorry if it’s wrong

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When jogging outside you accidently bump into a curb. Your feet stop but your body continues to move forward and you end up on t

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Inertia I think because I've heard it around school and in science

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3 years ago

Oil having a specific gravity of 0.9 is pumped as illustrated with a water jet pump. The water volume flowrate is 1 m3 /s. The w

love history [14]

Answer:

The rate at which the pump moves oil is 1 m³/s

Explanation:

Assumptions:

there is steady-state flow

oil and water are incompressible

first fluid is water, second fluid is oil and third fluid is the mixture of oil and water.

$\rho_1Q_1 + \rho_2Q_2 = \rho_3Q_3 -------equation (i)$

where;

ρ is the fluid density

Q is the volumetric flow rate

$Q_1 + Q_2 = Q_3--------equation (ii)$

Substitute in Q₃ in equation i

$\rho_1Q_1 + \rho_2Q_2 = \rho_3(Q_1 +Q_2)$

divide through by ρ₁

$\frac{\rho_1Q_1}{\rho_1}+ \frac{\rho_2Q_2}{\rho_1} =\frac{ \rho_3(Q_1 +Q_2)}{\rho_1}\\\\Note; \frac{\rho_2}{\rho_1} = \gamma_2 \ and \ \frac{\rho_3}{\rho_1} = \gamma_3\\\\Q_1 + \gamma_2Q_2 = \gamma_3(Q_1+Q_2)$

Make Q₂ the subject of the formula

$Q_2 = \frac{Q_1(1- \gamma_3)}{\gamma_3-\gamma_2} = \frac{1 (\frac{m^3}{s}) (1-0.95)}{0.95-0.9} = 1 \ \frac{m^3}{s}$

Therefore, the rate at which the pump moves oil is 1 m³/s

6 0

3 years ago

Um carro viaja de uma cidade A a uma cidade B, distantes 200km.seu percurso demora 4 horas ,pois decorrida uma hora de viagem ,o

Aleksandr-060686 [28]

Answer: B

Explanation:

5 0

3 years ago

A 1180kg car is moving at a speed of 85.5 km/h. Find the force needed to bring the car to rest in a distance of 300m

yarga [219]

Answer:

1110 N

Explanation:

First, find the acceleration.

Given:

Δx = 300 m

v₀ = 85.5 km/h = 23.75 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (23.75 m/s)² + 2a (300 m)

a = -0.94 m/s²

Find the force:

F = ma

F = (1180 kg) (-0.94 m/s²)

F = -1110 N

The magnitude of the force is 1110 N.

3 0

3 years ago

A piston motion moves a 25-kg hammerhead vertically down 1 m from rest to a velocity of 50 m/s in a stamping machine. What is th

Alja [10]

Answer:

31.005 KJ

Explanation:

We are given that

Mass of hammerhead=25 kg

Initial velocity,u=0

Final velocity,v=50 m/s

h=-1 m

h'=0

We have to find the change in total energy of the hammerhead.

Change in total energy= $E_2-E_1=m(u_2-u_1)+\frac{1}{2}m(v^2-u^2)+mg(h-h')$

Using the formula

Change in internal energy of hammerhead= $m(u_2-u_1)=0$

Change in total energy= $\frac{1}{2}(25)(50)^2+25\times 9.8(-1)$

Where $g=9.8m/s^2$

Change in total energy= $31005 J=\frac{31005}{1000}=31.005 KJ$

1 KJ=1000 J

3 0

3 years ago