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Lelechka [254]
3 years ago
13

Estimate the radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 9.5 cm from the center of the bul

b. Assume that light is completely absorbed. Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Given Information:  

Power of bulb = w = 25 W atts

distance = d = 9.5 cm = 0.095 m

Required Information:  

Radiation Pressure = ?

Answer:

Radiation Pressure =7.34x10⁻⁷ N/m²

Explanation:

We know that radiation pressure is given by

P = I/c

Where I is the intensity of radiation and is given by

I = w/4πd²

Where w is the power of the bulb in watts and d is the distance from the center of the bulb.

So the radiation pressure becomes

P = w/c4πd²

Where c = 3x10⁸ m/s is the speed of light

P = 25/(3x10⁸*4*π*0.095²)

P = 7.34x10⁻⁷ N/m²

Therefore, the radiation pressure due to a 25 W bulb at a distance of 9.5 cm from the center of the bulb is 7.34x10⁻⁷ N/m²

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Explanation:

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With "normal" gravity, we used a potential energy of mgh. Now with the gravity that is more accurate over longer distances we us
Artemon [7]

Answer:

A general solution is \Delta U=mh\frac{GM}{r^{2}}\frac{r}{r+\Delta h} and a particualr case is mgh, it is just to distance around the radius Earth.

Explanation:

We can use a general equation of the potential energy to understand the particular and general case:

The potential energy is defined as U=-\int F\cdot dx, we know that the gravitational force is F=GmM/r^{2}, so we could find the potential energy taking the integral of F.

U=-GmM/r (1)

We can find the particular case, just finding the gravitational potential energy difference:

\Delta U=U_{f}-U_{i}. Here Uf is the potential evaluated in r+Δh and Ui is the potential evaluated in r.

Using (1) we can calculate ΔU.

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Simplifying and combining terms we have a simplified expression.

\Delta U=mh\frac{GM}{r^{2}}\frac{r}{r+\Delta h} (2)

Let's call g=\frac{GM}{r^{2}}. It is the acceleration due to gravity on the Earth's surface, if r is the radius of Earth and M is the mass of the Earth and we can write (2) as ΔU=mgh, but if we have distance grader than r we should use (2), otherwise, we could get incorrect values of potential energy.

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Answer:

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