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Luda [366]
3 years ago
13

PLEASE HELP ASAP! 32 mins left! Give the sign of the electrodoes and the reaction of that occurs at each for both voltaic and el

ectrolytic cells. GIVING BRAINLIEST!! Please help, thanks in advance!!
Chemistry
1 answer:
Butoxors [25]3 years ago
3 0

Answer:

In a voltaic cell (one that happens spontaneously), electrons flow from a negative electrode to a positive electrode (anode  cathode). The reaction that happens is a redox reaction where the anode is oxidized (goes from a solid to an ion) and the cathode is reduced (going from an ion to a solid).

Explanation:

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Why is cell uncountable? ​
disa [49]

Answer:

Cells are uncountable becasue they move around your body, make up your skin and other organs as well. And because when you grow, the cells multiply, and that makes it very hard for scientists to count cells in a human's body.

Explanation:

Hope this helped!

3 0
4 years ago
Why should scientists control most possible variables in their experiments?
irina [24]
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8 0
3 years ago
Calculate the concentration of an aqueous solution of naoh that has a ph of 11.50
Reika [66]
NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions. 
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
pH + pOH = 14
Since pH = 11.50
pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 3.2 x 10⁻³ M
therefore [NaOH] = 3.2 x 10⁻³ M
7 0
3 years ago
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An adult mosquitoes lifespan is about 16 days how many minutes is that
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5 0
3 years ago
You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1
jeka57 [31]

Answer:

\boxed{\text{36 mL}}

Explanation:

1. Write the balanced chemical equation.

\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O

2. Calculate the moles of HCOOH

\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}

3. Calculate the moles of NaOH.

\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}

4. Calculate the volume of NaOH

c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}

3 0
3 years ago
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