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3 years ago

How are antibodies and receptor molecules function similarly

Chemistry

1 answer:

Montano1993 [528]3 years ago

7 0

Answer:

Antigens are molecules capable of stimulating an immune response. Each antigen has distinct surface features, or epitopes, resulting in specific responses. Antibodies (immunoglobins) are Y-shaped proteins produced by B cells of the immune system in response to exposure to antigens.

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Does anyone know how to make this a longer sentence?

Nadusha1986 [10]

Answer:

First, you have to analyze your problem or question. After you research and collect data about your topic, create a hypothesis to test to try and find the answer. After testing your hypothesis, come up with a conclusion based on the results.

7 0

3 years ago

Read 2 more answers

Analyze the role coefficients in a chemical reaction play in stoichiometry

kumpel [21]

Answer:

This is known as the coefficient factor

Explanation:The balanced equation makes it possible to convert information about one reactant or product to quantitative data about another element.

7 0

2 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago

Given the following equation: 2 K + Cl2 ---> 2 KCl

Ksivusya [100]

Answer:

2 moles of KCl will be produced

Explanation:

Given parameters:

Number of moles of K = 2 moles

Unknown:

Number of moles of KCl produced = ?

Solution:

To solve this problem;

Obtain a balanced chemical equation:

2K + Cl₂ → 2KCl ;

Since K is the limiting reactant, its amount will determine the extent of this reaction.

From the balanced equation;

2 moles of K will produce 2 moles of KCl

Given that 2 moles of K reacted, 2 moles of KCl will be produced

5 0

3 years ago

TRUE OR FALSE :Normal cells will not divide unless the nutrients they require are already presen True False

Diano4ka-milaya [45]

Answer:

False

Explanation:

Cell division is a primary procedure by all cells. This process in the life cycle of cells ensures that new cells (daughter cells) are produced. The two major process are; meiosis and mitosis.

Normal cells would divide if the nutrients required are not present, since water is the main nutrient required. But in some cases, the division process may lead to an effect on one or both daughter cells. This effect is called mutation, thereby mutated cells may be produced.

7 0

3 years ago